问题描述
我遇到了将两个表中的数据显示为JSON格式并使用yii2 restful api的问题.
I got the problem to display the data from two table into JSON format and working on yii2 restful api.
这是我的结构数据库:
TABLE `volunteer`(
`volunteer_id` int(11) NOT NULL auto_increment,
`state_id` int(11) null
TABLE `state`(
`state_id` int(11) NOT NULL auto_increment,
`state` varchar(225) null
volunteerController.php
public $modelClass = 'app\models\Volunteer';
public function behaviors()
{
return ArrayHelper::merge(parent::behaviors(),[
'verbs' => [
'class' => VerbFilter::className(),
'actions' => [
'delete' => ['post'],
],
],
]);
}
config/web.php
'rules' => [
['class' => 'yii\rest\UrlRule', 'controller' => ['volunteer','state','post']],
],
'request' => [
// !!! insert a secret key in the following (if it is empty) - this is required by cookie validation
'cookieValidationKey' => 'QMoK0GQoN7_VViTXxPdTISiOrITBI4Gy',
'parsers' => [
'application/json' => 'yii\web\JsonParser',
],
],
这是JSON格式的结果:
this is the result in JSON format:
[
{
"volunteer_id": 1,
"country_id": 1,
"state_id": 12,
}
]
所以结果不是我想要的.我想要的是state_id应该从表state返回状态数据,这意味着 state:New York .不返回state_id.如何解决这个问题呢 ?
so that result is not what I want. What I want is state_id should return state data from table state which means state : New York . Not return the state_id. How to solve this problem ?
推荐答案
这可以通过覆盖fields()
这样来完成:
This can be done with overriding fields()
like that:
public function fields()
{
return [
'volunteer_id',
'country_id',
'state' => function ($model) {
return $model->state->name; // Return related model property, correct according to your structure
},
];
}
此外,您可以使用with()
急于在prepareDataProvider()
方法中加载此关系.
Additionally you can eagerly load this relation in prepareDataProvider()
method using with()
.
官方文档:
- Overriding fields()
- Customizing actions
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