问题描述
当我尝试坚持我的模型时遇到问题。创建EntityManagerFactory时抛出异常：
$ b
I have a problem when I try to persist my model. An exception is thrown when creating the EntityManagerFactory:
这两个实体的代码如下：
The code for the two entities is as follows:
@Entity
public class EntityOne
{
@OneToOne(cascade = CascadeType.ALL, targetEntity = EntityTwo.class)
@JoinColumn(name = "ENTITY_TWO_ID")
private EntityTwo entityTwo;
...
}
@Entity
public class EntityTwo
{
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
@Column(name = "ELEMENT_ID")
private Long element_id;
...
}
有人可以告诉我我的模型有什么问题？
在此先感谢。
Can someone please tell me what is wrong with my model?Thanks in advance.
推荐答案
嗯，这个消息是自我解释的：列类型不匹配在Java级别使用的类型。如果您想痛斥 Long ，请使用 BIGINT 作为列类型。
Well, the message is self-explaining: the column type doesn't match the type used at the Java level. If you want to sore a Long, use a BIGINT as column type.
更新：我使用Hibernate测试了您的代码作为JPA提供程序，并且 ENTITYONE.ENTITY_TWO_ID 生成为 BIGINT 栏。也许你生成了你的表并在以后改变了Java类型而不再生成物理模型。我的建议是放弃表格并重试。
Update: I tested your code with Hibernate as JPA provider and ENTITYONE.ENTITY_TWO_ID is generated as a BIGINT column. Maybe you generated your table and changed the Java type later without regenerating the physical model. My suggestion would be to drop the table and to try again.
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