从A移动图片使用JavaScript到B

本文介绍了从A移动图片使用JavaScript到B的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述 29岁程序员，3月因学历无情被辞！ 它的我第一次和时间在这里我不知道该怎么缩进此深表歉意：/Its my first time here and I don't know how to indent this sorry :/有我一个车的形象，我想它在屏幕上移动，就像它是驾驶。一旦做到这一点，我会缩放形象出现，就好像它正在远离的（和越来越小）。I have an image of a van and I am trying to move it across the screen to as if it is driving.Once that is done I will scale the image to appear as if it is moving away (and getting smaller).我需要这在标准的JavaScript来完成，没有任何包（如JQuery的），请。I need this to be done in standard javascript without any packages (such as JQuery) please.我所得到的是其中的一个原因，我不能打破一辆面包车沿两条路径，而不是一个运动。在错误的方向也移动（它应该沿着路径Y = -25X移动，使每个25像素向右移动，应该向上移动1像素）。What I've got is a van which for a reason I can't break down is moving along 2 paths instead of one. Also moving in the wrong direction (it should move along the path y=-25x so that every 25 pixels moved to the right it should move 1 pixel upwards).要说明什么，我想实现的，请参阅本图片： http://i.stack.imgur.com/9WIfr.jpgTo illustrate what I am trying to achieve, please see this image:http://i.stack.imgur.com/9WIfr.jpg这是我的JavaScript文件：This is my javascript file:var viewWidth = 800;var viewHeight = 480;var fps = 30;var delay = getFrame(fps);var vanWidth, vanHeight, vanObj;function initVan() { vanObj = document.getElementById("van"); vanObj.style.position = "absolute"; vanObj.src = "pics/delivery/van.png"; vanWidth = 413; vanHeight = 241; var startX = 0-vanWidth; var startY = viewHeight-vanHeight; setPosition(startX,startY); transition(startX,startY,3000);}function transition(startX,startY,time) { //the intention of this is to follow a path y=-25x in mathematical terms var endX = viewWidth; var endY = startY-(endX/-25); //note that this is the velocity per millisecond var velocityX = (endX-startX)/time; var velocityY = (endY-startY)/time; alert(endY+", "+startY); move(velocityX,velocityY,endX,endY);}function move(vX,vY,eX,eY) { var posX = getX(); var posY = getY(); if (posX<=eX || posY<=eY) { //velocityX (in milliseconds) * delay = the amount of pixels moved in one frame @fps=30 var moveX = vX*delay; var moveY = vY*delay; var newX = posX+moveX; var newY = posY+moveY; setPosition(newX,newY); setTimeout(function() { move(vX,vY,eX,eY); }, delay); }}function getX() { return vanObj.offsetLeft;}function getY() { return vanObj.offsetTop;}function setPosition(newX,newY) { vanObj.style.left = newY + "px"; vanObj.style.top = newX + "px";}function setSize(scaleX,scaleY) { vanWidth *= scaleX; vanHeight *= scaleY; vanObj.width = vanWidth; vanObj.height = vanHeight;}function getFrame(fps) { return Math.floor(1000/fps);}这是我的HTML文件：This is my HTML file: ＆LT;脚本类型=文/ JavaScript的SRC =delivery.js＆GT; ＆LT; / SCRIPT＆GT;结果＆LT;身体的onLoad =initVan（）;＆GT;结果＆LT; IMG ID =面包车WIDTH = 413 HEIGHT = 241 /＆GT;推荐答案除非你有一个无库的要求，或者特别喜欢重新发明轮子，我想解决这个使用jQuery的特效库，特别是.animate： http://api.jquery.com/animate/ 。看到页面上的第一个例子。Unless you have a no-libraries requirement, or particularly enjoy reinventing the wheel, I'd solve this using jQuery's effects library, and in particular .animate: http://api.jquery.com/animate/. See the first example on that page.$(document).ready(function() { $('#van') .attr({ width: 413, height: 241 //etc. }) .animate({ width: "70%", height: "70%" //etc. }, 3000);});减code意味着更少的维护。意味着满意的顾客。Less code means less maintenance. Means happy customer. 这篇关于从A移动图片使用JavaScript到B的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！ 上岸，阿里云！