XNA - Mouse.Left按钮获取更新多次执行

问题描述

我想提出一个井字棋游戏。我需要检查，如果一个球员点击他们已经点击了一个正方形。

I am making a Tic-Tac-Toe game. I need to check if a player is clicking on a square they have already clicked.

问题是显示在第一个错误单击本身。
我更新的代码是：

Problem is error is shown in the first click itself.My update code is:

    MouseState mouse = Mouse.GetState();
    int x, y;
    int go = 0;
    if (mouse.LeftButton == ButtonState.Pressed)
    {
        showerror = 0;
        gamestate = 1;
        x = mouse.X;
        y = mouse.Y;
        int getx = x / squaresize;
        int gety = y / squaresize;
        for (int i = 0; i < 3; i++)
        {
            if (go == 1)
            {
                break;
            }
            for (int j = 0; j < 3; j++)
            {
                if (getx == i && gety == j)
                {
                    if (storex[i, j] == 0)
                    {
                       showerror = 1;
                    }
                    go = 1;
                    if (showerror != 1)
                    {
                        loc = i;
                        loc2 = j;
                        storex[i, j] = 0;
                        break;
                    }
                }
            }
        }
    }

showerror 是只要单击左键设置为0。我的矩阵是用于存储信息的3×3矩阵。如果是0，这意味着它已经被clicked.So在循环我检查店[I，J] == 0 然后设置 showerror 1。
现在在绘制函数我提出这个要求showerror

showerror is set to 0 whenever left button is clicked. My matrix is a 3x3 matrix for storing information. If it is 0 that means it has been already clicked.So in the loop I check if store[i,j] == 0 then set showerror to 1.Now in the draw function I made this call for showerror

spriteBatch.Begin();
if (showerror == 1)
{
    spriteBatch.Draw(invalid, new Rectangle(25, 280, 105, 19), Color.White);
}
spriteBatch.End();

但问题是每当我在空方点击它变成十字但误差会shown.Please帮助我

Problem is whenever i click on empty square it turns into cross but error gets shown.Please help me out

推荐答案

如何解决：

添加一个新的全局变量来存储来自前一帧的鼠标状态：

Add a new global variable to store the mouse state from the previous frame:

MouseState oldMouseState;

目前您的更新方法的开始（或结束），添加此，

At the very beginning (or end) of your update method, add this,

oldMouseState = mouse;

和替换

if (mouse.LeftButton == ButtonState.Pressed)

与

if (mouse.LeftButton == ButtonState.Pressed && oldMouseState.LeftButton == ButtonState.Released)

这样做是什么检查，如果你做了一个点击，其释放的键，然后按下，因为有时你可能持有多帧的关键

What this does is check if you made one click, having the key released then pressing, because sometimes you may hold the key for multiple frames.

通过设置 oldMouseState：

To Recap:

要回顾更新之前， currentMouseState （或者你用它做后），您garantee的 oldMouseState 将在后面 currentMouseState 。使用这个你可以检查一个按钮下跌前一帧，但现在不是了，并相应地处理输入。一个好主意延长，这是写一些推广方法，如 IsHolding（）， IsClicking（）等。

By setting oldMouseState before you update the currentMouseState (Or after you are done with it), you garantee that oldMouseState will be one frame behind currentMouseState. Using this you can check if a button was down the previous frame, but not anymore, and handle input accordingly. A good idea to extend this is write some extension methods like IsHolding(), IsClicking(), etc.

在简单的代码：

private MouseState oldMouseState, currentMouseState;
protected override void Update(GameTime gameTime)
{
     oldMouseState = currentMouseState;
     currentMouseState = Mouse.GetState();
     //TODO: Update your code here
}

这篇关于XNA - Mouse.Left按钮获取更新多次执行的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！