本文介绍了安装后无法执行pyspark的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！
问题描述
我手动复制了 spark-2.4.0-bin-hadoop2.7.tgz 并解压缩。然后我在 .bash_profile 中输入如下：
I have manually copied the spark-2.4.0-bin-hadoop2.7.tgz and extracted. Then I have made entry in .bash_profile as below:
我确定我已在下面安装 jdk.Response ：
I'm sure that i have installed jdk.Response below:
错误如下：
Python 3.7.0 (default, Jun 28 2018, 07:39:16)
[Clang 4.0.1 (tags/RELEASE_401/final)] :: Anaconda, Inc. on darwin
Type "help", "copyright", "credits" or "license" for more information.
Exception in thread "main" java.lang.ExceptionInInitializerError
at org.apache.hadoop.util.StringUtils.<clinit>(StringUtils.java:80)
at org.apache.hadoop.security.SecurityUtil.getAuthenticationMethod(SecurityUtil.java:611)
at org.apache.hadoop.security.UserGroupInformation.initialize(UserGroupInformation.java:273)
at org.apache.hadoop.security.UserGroupInformation.ensureInitialized(UserGroupInformation.java:261)
at org.apache.hadoop.security.UserGroupInformation.loginUserFromSubject(UserGroupInformation.java:791)
at org.apache.hadoop.security.UserGroupInformation.getLoginUser(UserGroupInformation.java:761)
at org.apache.hadoop.security.UserGroupInformation.getCurrentUser(UserGroupInformation.java:634)
at org.apache.spark.util.Utils$$anonfun$getCurrentUserName$1.apply(Utils.scala:2422)
at org.apache.spark.util.Utils$$anonfun$getCurrentUserName$1.apply(Utils.scala:2422)
at scala.Option.getOrElse(Option.scala:121)
at org.apache.spark.util.Utils$.getCurrentUserName(Utils.scala:2422)
at org.apache.spark.SecurityManager.<init>(SecurityManager.scala:79)
at org.apache.spark.deploy.SparkSubmit.secMgr$lzycompute$1(SparkSubmit.scala:359)
at org.apache.spark.deploy.SparkSubmit.org$apache$spark$deploy$SparkSubmit$$secMgr$1(SparkSubmit.scala:359)
at org.apache.spark.deploy.SparkSubmit$$anonfun$prepareSubmitEnvironment$7.apply(SparkSubmit.scala:367)
at org.apache.spark.deploy.SparkSubmit$$anonfun$prepareSubmitEnvironment$7.apply(SparkSubmit.scala:367)
at scala.Option.map(Option.scala:146)
at org.apache.spark.deploy.SparkSubmit.prepareSubmitEnvironment(SparkSubmit.scala:366)
at org.apache.spark.deploy.SparkSubmit.submit(SparkSubmit.scala:143)
at org.apache.spark.deploy.SparkSubmit.doSubmit(SparkSubmit.scala:86)
at org.apache.spark.deploy.SparkSubmit$$anon$2.doSubmit(SparkSubmit.scala:924)
at org.apache.spark.deploy.SparkSubmit$.main(SparkSubmit.scala:933)
at org.apache.spark.deploy.SparkSubmit.main(SparkSubmit.scala)
Caused by: java.lang.StringIndexOutOfBoundsException: begin 0, end 3, length 2
at java.base/java.lang.String.checkBoundsBeginEnd(String.java:3319)
at java.base/java.lang.String.substring(String.java:1874)
at org.apache.hadoop.util.Shell.<clinit>(Shell.java:52)
... 23 more
Traceback (most recent call last):
File "/Users/suman/Pyspark/spark-2.4.0-bin-hadoop2.7/python/pyspark/shell.py", line 38, in <module>
SparkContext._ensure_initialized()
File "/Users/suman/Pyspark/spark-2.4.0-bin-hadoop2.7/python/pyspark/context.py", line 298, in _ensure_initialized
SparkContext._gateway = gateway or launch_gateway(conf)
File "/Users/suman/Pyspark/spark-2.4.0-bin-hadoop2.7/python/pyspark/java_gateway.py", line 94, in launch_gateway
raise Exception("Java gateway process exited before sending its port number")
Exception: Java gateway process exited before sending its port number
推荐答案
我在这里的答案中尝试了所有内容，包括karma&苏曼的答案，没有任何效果。我将此路径添加到.bash_profile并且它对我有用：
I tried everything in the answers here including karma & suman's answers and nothing worked. I added this path to .bash_profile and it worked for me:
export JAVA_HOME="/Library/Internet\ Plug-Ins/JavaAppletPlugin.plugin/Contents/Home -v 1.8"
我希望它适合你。
这篇关于安装后无法执行pyspark的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！