问题描述
以下PHP程序替换符号！£$％^&用空值
The following PHP program replaces the symbols !£$%^& with nulls
<?php
$string = "This is some text and numbers 12345 and symbols !£$%^&";
$new_string = ereg_replace("[^A-Za-z0-9 (),.]", "", $string);
echo "Old string is: ".$string."<br />New string is: ".$new_string;
?>
输出：
旧字符串为：这是一些文本和数字12345和符号！£$％^&
新字符串是：这是一些文本和数字12345和符号
Old string is: This is some text and numbers 12345 and symbols !£$%^&
New string is: This is some text and numbers 12345 and symbols
但是，我了解到不建议使用ereg_replace（）函数，而应改用preg_replace（）函数。我做了这样的替换：
But, I have learned that the function ereg_replace() has been deprecated and that I should use the function preg_replace() instead. I made the substitution like so:
<?php
$string = "This is some text and numbers 12345 and symbols !£$%^&";
$new_string = preg_replace("[^A-Za-z0-9 (),.]", "", $string);
echo "Old string is: ".$string."<br />New string is: ".$new_string;
?>
但输出错误：
旧字符串是：这是一些文本，数字12345和符号！£$％^&
新字符串是：这是一些文本和数字12345和符号！£$％^&
Old string is: This is some text and numbers 12345 and symbols !£$%^&New string is: This is some text and numbers 12345 and symbols !£$%^&
我怎么了？我该如何解决？
What did I do wrong? How do I fix it?
推荐答案
您似乎在正则表达式周围缺少标记。请改用此方法（注意图案周围的斜线）。
You seem to be missing markers around the regular expression. Try this instead (note the slashes around the pattern).
$string = "This is some text and numbers 12345 and symbols !$%^&";
$new_string = preg_replace("/[^A-Za-z0-9 (),.]/", "", $string);
echo "Old string is: ".$string."<br />New string is: ".$new_string;
您可以使用任意字符作为标记，只要双方都找到相同的字符即可。如果您的模式匹配 / 字符，则非常有用。因此，这也是有效的：
You can use any character for the markers as long as the same one is found on both sides. Very useful if your pattern is matching / characters. So this is also valid:
$string = "This is some text and numbers 12345 and symbols !$%^&";
$new_string = preg_replace("~[^A-Za-z0-9 (),.]~", "", $string);
echo "Old string is: ".$string."<br />New string is: ".$new_string;
这篇关于用preg_replace（）替换不推荐使用的ereg_replace（）无效的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！