问题描述
我正在使用mySQL,并且处于一种情况下,我需要从一个表中选择与父表->另一表中的子数据层次结构中任何级别的ID匹配的表中的数据.
此外,我想通过编写良好的SQL查询而不是PHP代码中的递归函数来解决此问题,因为此功能将被大量使用.
我确实尝试搜索,但偶然发现了许多类似的问题(大多数问题已得到解决),但是没有一个问题对我有帮助.
为帮助说明情况,这是我当前的设置
表格文章":
- article_id
- category_id
- ...
表格类别
- category_id
- parent_id
- ...
我需要从"articles.category_id"为10的"articles"中选择所有文章.还要从"categories.category_id" 10所属的树中接收所有类别的所有文章. /p>
意思是,其中"10"是父母及其所有孩子,向上则是10是孩子及其所有父母.
可能没有递归的php函数吗?
谢谢.
在MySQL
中可以做到这一点,但需要一些努力.您必须编写这样的函数:
CREATE FUNCTION hierarchy_connect_by_parent_eq_prior_id(value INT) RETURNS INT
NOT DETERMINISTIC
READS SQL DATA
BEGIN
DECLARE _id INT;
DECLARE _parent INT;
DECLARE _next INT;
DECLARE CONTINUE HANDLER FOR NOT FOUND SET @id = NULL;
SET _parent = @id;
SET _id = -1;
IF @id IS NULL THEN
RETURN NULL;
END IF;
LOOP
SELECT MIN(id)
INTO @id
FROM categories
WHERE parent = _parent
AND id > _id;
IF @id IS NOT NULL OR _parent = @start_with THEN
SET @level = @level + 1;
RETURN @id;
END IF;
SET @level := @level - 1;
SELECT id, parent
INTO _id, _parent
FROM categories
WHERE id = _parent;
END LOOP;
END
并在查询中使用它:
SELECT id, parent, level
FROM (
SELECT hierarchy_connect_by_parent_eq_prior_id(id) AS id, @level AS level
FROM (
SELECT @start_with := 0,
@id := @start_with,
@level := 0
) vars, categories
WHERE @id IS NOT NULL
) ho
JOIN categories hi
ON hi.id = ho.id
有关更多详细信息,请参见我的博客中的条目:
I'm working with mySQL, and I'm in a situation where I need to select data from one table that matches an ID at any level in parent -> child data hierarchy in the other table.
Further more, I would like to resolve this with a well written SQL query, rather than a recursive function in my PHP code, as this feature will be used quite a bit.
I did try searching, and I have stumbled upon numerous similar problems (most of them being resolved), however none of them helped me.
To help illustrate the situation, here's my current setup
table "articles":
- article_id
- category_id
- ...
table categories
- category_id
- parent_id
- ...
I need to select all the articles from "articles" where "articles.category_id" is, let's say, 10. But also receive all the articles from all categories from the tree the "categories.category_id" 10 belongs to.
Meaning, where "10" is the parent and all of it's children, and upwards where 10 is the child and all of it's parents.
Possible without a recursive php function?
Thank you.
This is possible to do in MySQL
, but it takes a little effort. You'll have to write a function like this:
CREATE FUNCTION hierarchy_connect_by_parent_eq_prior_id(value INT) RETURNS INT
NOT DETERMINISTIC
READS SQL DATA
BEGIN
DECLARE _id INT;
DECLARE _parent INT;
DECLARE _next INT;
DECLARE CONTINUE HANDLER FOR NOT FOUND SET @id = NULL;
SET _parent = @id;
SET _id = -1;
IF @id IS NULL THEN
RETURN NULL;
END IF;
LOOP
SELECT MIN(id)
INTO @id
FROM categories
WHERE parent = _parent
AND id > _id;
IF @id IS NOT NULL OR _parent = @start_with THEN
SET @level = @level + 1;
RETURN @id;
END IF;
SET @level := @level - 1;
SELECT id, parent
INTO _id, _parent
FROM categories
WHERE id = _parent;
END LOOP;
END
and use it in a query:
SELECT id, parent, level
FROM (
SELECT hierarchy_connect_by_parent_eq_prior_id(id) AS id, @level AS level
FROM (
SELECT @start_with := 0,
@id := @start_with,
@level := 0
) vars, categories
WHERE @id IS NOT NULL
) ho
JOIN categories hi
ON hi.id = ho.id
See this entry in my blog for more detail:
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