Servlet错误HTTP状态405 - HTTP方法GET不受此URL支持

问题描述

我写了下面的Servlet（Search1.java）：

  package ergasia; 
 
 import java.sql。*; 
 import java.io. *; 
 import javax.servlet。*; 
 import javax.servlet.http。*; 
 import java.util.ArrayList; 
 $ b $ public class Search1 extends HttpServlet 
 {
 @Override $ b $ public void doPost（HttpServletRequest request，HttpServletResponse response）
 throws ServletException，IOException 
 {
 response.setContentType（text / html）; 
连接连接=空; 
 String url =jdbc：mysql：// localhost：3306 /; 
 String dbName =ergasia; 
 String user =root; 
字符串密码=密码; 
 PreparedStatement selectProteins = null; 
 ResultSet resultSet = null; 
 ArrayList al = null; 
 
尝试{
 connection = DriverManager.getConnection（url + dbName，user，password）; 
 String keyword = request.getParameter（keyword）; 
 selectProteins = connection.prepareStatement（SELECT * FROM protein WHERE proteinName LIKE？）; 
 selectProteins.setString（1，％+ keyword +％）; 
 resultSet = selectProteins.executeQuery（）; 
 
 ArrayList keyword_list = new ArrayList（）; 
 
 while（resultSet.next（））{
 al = new ArrayList（）; 
 al.add（resultSet.getString（1））; 
 al.add（resultSet.getString（2））; 
 al.add（resultSet.getString（3））; 
 al.add（resultSet.getString（4））; 
 al.add（resultSet.getString（5））; 
 al.add（resultSet.getString（6））; 
 al.add（resultSet.getString（7））; 
 keyword_list.add（al）; 
} 
 
 request.setAttribute（results，keyword_list）; 
 RequestDispatcher view = request.getRequestDispatcher（/ search_proteins.jsp）; 
 view.forward（request，response）; 
 
 catch（SQLException e）{
 e.printStackTrace（）; 
 
 
 @Override 
 public String getServletInfo（）{
 returninfo; 
} 
} 
  

使用以下命令从jsp页面访问：

 < form method =postaction =/ ergasia / Search1> 
  

但是当我尝试运行它时，tomcat给了我下面的错误：
HTTP Status 405 - 这个URL不支持HTTP方法GET
类型：状态报告
消息：这个URL不支持HTTP方法GET
描述：指定的HTTP方法不允许被请求的资源。

以下是我的web.xml文件：

 < xml version =1.0encoding =UTF-8？> 
< web-app version =2.5xmlns =http://java.sun.com/xml/ns/javaeexmlns：xsi =http://www.w3.org/2001/ XMLSchema-instancexsi：schemaLocation =http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd\"> 
< servlet> 
< servlet-name> Search_proteins< / servlet-name> 
< servlet-class> ergasia.Search1< / servlet-class> 
< / servlet> 
< servlet-mapping> 
< servlet-name> Search_proteins< / servlet-name> 
< url-pattern> / Search_proteins< / url-pattern> 
< / servlet-mapping> 
< welcome-file-list> 
< welcome-file> index.jsp< / welcome-file> 
< / welcome-file-list> 
< / web-app> 
  

你能帮我找出我做错了什么吗？

不幸的是我现在还不能发布图片，所以这里是我的配置，也许会有帮助：

解决方案

您的servlet没有像 / ergasia / Search1 ，试试这个：

 < form method =postaction = Search_proteins > 
  

I've written the following Servlet (Search1.java):

package ergasia;

import java.sql.*;
import java.io.*;
import javax.servlet.*;
import javax.servlet.http.*;
import java.util.ArrayList;

public class Search1 extends HttpServlet
{
   @Override
   public void doPost(HttpServletRequest request, HttpServletResponse response)
      throws ServletException, IOException
   {
    response.setContentType("text/html");
    Connection connection= null;
    String url = "jdbc:mysql://localhost:3306/";
    String dbName = "ergasia";
    String user = "root";
    String password = "password";
    PreparedStatement selectProteins = null;
    ResultSet resultSet = null;
    ArrayList al = null;

        try {
            connection = DriverManager.getConnection(url + dbName, user, password);
            String keyword = request.getParameter("keyword");
            selectProteins = connection.prepareStatement("SELECT * FROM protein WHERE proteinName LIKE ?");
            selectProteins.setString(1, "%" + keyword + "%");
            resultSet = selectProteins.executeQuery();

            ArrayList keyword_list = new ArrayList();

                while (resultSet.next()) {
                    al = new ArrayList();
                    al.add(resultSet.getString(1));
                    al.add(resultSet.getString(2));
                    al.add(resultSet.getString(3));
                    al.add(resultSet.getString(4));
                    al.add(resultSet.getString(5));
                    al.add(resultSet.getString(6));
                    al.add(resultSet.getString(7));
                    keyword_list.add(al);
                }

            request.setAttribute("results", keyword_list);
            RequestDispatcher view = request.getRequestDispatcher("/search_proteins.jsp");
            view.forward(request, response);

        } catch (SQLException e) {
            e.printStackTrace();
        }
    }
    @Override
    public String getServletInfo() {
        return "info";
    }
}

that I access from a jsp page with the following command:

<form method="post" action="/ergasia/Search1">

but when I try to run it tomcat gives me the following error:HTTP Status 405 - HTTP method GET is not supported by this URLtype:Status reportmessage:HTTP method GET is not supported by this URLdescription:The specified HTTP method is not allowed for the requested resource.

Here's my web.xml file too:

<?xml version="1.0" encoding="UTF-8"?>
<web-app version="2.5" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd">
    <servlet>
        <servlet-name>Search_proteins</servlet-name>
        <servlet-class>ergasia.Search1</servlet-class>
    </servlet>
    <servlet-mapping>
        <servlet-name>Search_proteins</servlet-name>
        <url-pattern>/Search_proteins</url-pattern>
    </servlet-mapping>
    <welcome-file-list>
        <welcome-file>index.jsp</welcome-file>
    </welcome-file-list>
</web-app>

Could you please help me find what I've done wrong?

Unfortunately I can't post images yet, so here is my configuration, maybe it'll help:1

解决方案

You servlet doesn't have url-pattern as /ergasia/Search1, try this instead:

<form method="post" action="Search_proteins">

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