std :: for_each，object with operator（）重载不维护状态

问题描述

在尝试回答这个问题我想出了以下代码：

In trying to answer this question I came up with the following code:

#include <string>
#include <iostream>
#include <algorithm>
#include <vector>

class Sizes
{
public:
    void operator() ( std::vector<int> v ) {
        sizeVec.push_back( v.size() );
    }
    std::vector<int> sizeVec;
};

void outFunc (int i) {
    std::cout << " " << i;
}
int _tmain(int argc, _TCHAR* argv[])
{
    std::vector<std::vector<int>> twodVec;

    std::vector<int> vec;
    vec.push_back( 6 );
    twodVec.push_back( vec );
    vec.push_back( 3 );
    twodVec.push_back( vec );
    vec.push_back( 8 );
    twodVec.push_back( vec );
    vec.push_back( 3 );
    twodVec.push_back( vec );

    Sizes sizes;
    std::for_each( twodVec.begin(), twodVec.end(), sizes );
    std::for_each( sizes.sizeVec.begin(), sizes.sizeVec.end(), outFunc );

    return 0;
}

随着每个呼叫按预期增加。但是当第二个std :: foreach被调用的时候，sizeVec是空的...我已经创建了一个工作，涉及传递一个向量到Sizes，但任何人都知道发生了什么

Debugging this shows Sizes::operator() being called and the size of sizeVec increasing with each call as expected. However when the second std::foreach is called the sizeVec is empty... I've created a work around involving passing a vector into Sizes but does anyone know what's going on

推荐答案

std :: for_each 通过值接受函数，而不是 em>，因此原始对象不受影响。您需要：

std::for_each takes a functor by value, not by reference, so the original object is unaffected. You need to do:

sizes = std::for_each( twodVec.begin(), twodVec.end(), sizes );

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