问题描述
我使用Debian操作系统，我试图指向cmake哪里是我的Qt4。
I am using Debian OS and I'm trying to point to cmake where is my Qt4.
我尝试构建qjson库及其CMakeLists.txt：
I try to build qjson library and with its CMakeLists.txt:http://pastebin.com/fKNp0Qgy
我得到：
Qt5 not found, searching for Qt4
qmake: could not exec '/usr/lib/x86_64-linux-gnu/qt4/bin/qmake': No such file or directory
CMake Error at /usr/share/cmake-2.8/Modules/FindQt4.cmake:1386 (message):
Found unsuitable Qt version "" from NOTFOUND, this code requires Qt 4.x
Call Stack (most recent call first):
CMakeLists.txt:55 (FIND_PACKAGE)
-- Configuring incomplete, errors occurred!
我不熟悉CMake和Qt配置，但我很好奇什么设置力CMake FIND_PACKAGE为qmake查看'/ usr / lib / x86_64-linux-gnu / qt4 / bin / qmake'。
我从源代码安装了Qt 4.8.5，我的Qt4 bin文件夹位于完全不同的目录中。
I'm not familiar with CMake and Qt config, but I'm curious what setting force CMake FIND_PACKAGE to look into '/usr/lib/x86_64-linux-gnu/qt4/bin/qmake' for qmake.I have installed Qt 4.8.5 from source and I have Qt4 bin folder in completely different directory.
推荐答案
解决我的问题。
使用 grep 命令寻找QT_SELECT我发现QT_SELECT与 /usr/lib/x86_64-linux-gnu/qt-default/qtchooser/default.conf 文件。从默认文件名，我认为它是被看作是QT_SELECT。其他配置 qtchooser -l 在 / usr / share / qtchooser / 和 usr / lib / x86_64-linux-gnu / qtchooser 目录。
Looking for QT_SELECT with grep command I found that QT_SELECT is related to /usr/lib/x86_64-linux-gnu/qt-default/qtchooser/default.conf file. From the "default" file name I assumed that it is what is seen as QT_SELECT. Other configs presented with qtchooser -l are in /usr/share/qtchooser/ and /usr/lib/x86_64-linux-gnu/qtchooser directories.
这样的配置文件有两行路径。我只是改变了这些行，首先指向我的Qt bin目录，然后指向我的Qt lib目录。然后我可以看到 qtchooser -print-env 显示 QTTOOLDIR 和 QTLIBDIR 到我的Qt。
Such a config file has two lines with paths. I just changed these lines, first pointing to my Qt bin directory and second pointing to my Qt lib directory. Then I could see that qtchooser -print-env shows QTTOOLDIR and QTLIBDIR to my Qt.
然后我可以很容易地构建qjson库与CMake，Qt4被正确找到。
Then I could easily build qjson library with CMake, Qt4 was found correctly.
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