使用DispatcherMiddleware包装的Flask应用程序不再具有test_client

问题描述

 来包装应用程序， / code>  - 我们会得到类似于
  AttributeError的错误：'DispatcherMiddleware'对象没有'test_client'属性。
 
 
 
有没有办法测试烧瓶应用的组成？ 
 
 
 
我们希望能做到这样的事情： 
 
 
  cls .client = my_app.all_apps.test_client（）
  
当 all_apps 是中间件：
 
 
  all_apps = DispatcherMiddleware（my_app，{
'/ backend'：backend_app， 
}）
  
 
 
解决方案
一个Flask应用程序，包装并替换应用程序的 wsgi_app 属性。您正在使用对其他WSGI应用程序的引用来替换对Flask应用程序的引用，该应用程序显然不具有相同的属性。通过替换 wsgi_app ，您保留对Flask应用程序的引用，但更改支持该应用程序的WSGI可调用。
 
 
 <$ p $  app.wsgi_app = DispatcherMiddleware（app.wsgi_app，{
'/ backend'：backend_app 
}）
  

We can obtain test_client for sample application in way like:

class MyTestCase(unittest.TestCase):
    @classmethod
    def setUpClass(cls):
        my_app.app.config['TESTING'] = True
        cls.client = my_app.app.test_client()

However, if we wrap app with DispatcherMiddleware - we will get error like AttributeError: 'DispatcherMiddleware' object has no attribute 'test_client'.

Are there way to test composition of flask applications?

We want to be able to do something like:

cls.client = my_app.all_apps.test_client()

When all_apps is middleware like:

all_apps = DispatcherMiddleware(my_app, {
    '/backend': backend_app,
})

解决方案

To add WSGI middleware to a Flask app, wrap and replace the app's wsgi_app attribute. You're replacing the reference to the Flask app with a reference to some other WSGI app, which obviously won't have the same properties. By replacing wsgi_app, you retain the reference to the Flask app but change the WSGI callable that backs it.

app.wsgi_app = DispatcherMiddleware(app.wsgi_app, {
    '/backend': backend_app
})

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