问题描述
我需要同时在屏幕上移动3个不同的MovieClip. (从下到上)使用Caurina之类的补间类，不执行此操作的最佳方法是什么?
I've 3 different MovieClips that I need to move at the same time across the screen. (From bottom to top)What is the best way of doing this without using a tweening class like Caurina?
谢谢你的提示.
推荐答案
您可以在显示对象的父容器中添加事件侦听器，以监听Event.ENTER_FRAME事件.在每个Event.ENTER_FRAME事件上，您都可以像下面的示例那样简单地减小显示对象的y属性.
You could add an event listener to the parent container of the display objects which listens for the Event.ENTER_FRAME event. On each Event.ENTER_FRAME event you simply decrement the y property of the display objects like in the following example.
package
{
import flash.display.Sprite;
import flash.events.Event;
[SWF(width="600", height="500")]
public class Main extends Sprite
{
private var _squares:Vector.<Square>;
public function Main():void
{
if (stage) init();
else addEventListener(Event.ADDED_TO_STAGE, init);
}// end function
private function init(e:Event = null):void
{
removeEventListener(Event.ADDED_TO_STAGE, init);
_squares = new Vector.<Square>();
var redSquare:Square = new Square(0xFF0000, 100);
redSquare.x = 0;
redSquare.y = 400;
addChild(redSquare);
var greenSquare:Square = new Square(0x00FF00, 100);
greenSquare.x = 300;
greenSquare.y = 300;
addChild(greenSquare);
var blueSquare:Square = new Square(0x0000FF, 100);
blueSquare.x = 500;
blueSquare.y = 100;
addChild(blueSquare);
_squares.push(redSquare, greenSquare, blueSquare);
addEventListener(Event.ENTER_FRAME, onEnterFrame);
}// end function
private function onEnterFrame(e:Event):void
{
for each(var square:Square in _squares)
{
if (square.y > 0) square.y -= 5;
}// end for
}// end function
}// end class
}// end package
import flash.display.Sprite;
internal class Square extends Sprite
{
public function Square(color:uint, size:Number)
{
graphics.beginFill(color);
graphics.drawRect(0, 0, size, size);
graphics.endFill();
}// end function
}// end function
我认为，即使您只使用Greensock的补间平台，您仍可以使自己的生活更轻松代替.
I think you'd be making life easier for yourself though if you simply used Greensock's Tweening platform instead.
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