问题描述
我目前正在将代码从R2012a迁移到R2013b.
I'm currently migrating code from R2012a to R2013b.
我注意到unique函数的行为已更改:
I noticed that the unique function behavior has changed:
R2012a
>> size(unique([]))
ans =
0 0
R2013b
>> size(unique([]))
ans =
0 1
在我看来，将x删除后，0x0矩阵将变为0x1矩阵，这与我的直觉相反，这实际上是唯一函数所做的事情.有人对此有道理吗?
It seems counter-intuitive to me that a 0x0 matrix would become a 0x1 matrix after removing doublons, which is essentially what the unique function does. Does anybody has a rationale for this?
推荐答案
如果您需要使用旧的行为，则R2013a的行为已更改:
The behaviour has changed with R2013a, if you need the old behaviour use:
size(unique([],'legacy'))
如果两个版本都需要代码，我建议编写一些函数，新版本调用unique(x,'legacy')，旧版本调用unique(x).
If you need code for both versions, I would recommend to write some function which calls unique(x,'legacy') for new versions and unique(x) for old versions.
btw:与union，intersect，setdiff，setxor和ismember
btw: same issue with union, intersect, setdiff, setxor and ismember
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