将类添加到 Django label_tag() 输出

问题描述

我需要某种方法将类属性添加到表单字段的 label_tag() 方法的输出中.

I need some way to add a class attribute to the output of the label_tag() method for a forms field.

我发现可以传入 attrs 字典，并且我已经在 shell 中对其进行了测试，我可以执行以下操作:

I see that there is the ability to pass in an attrs dictionary and I have tested it in the shell and I can do something like:

for field in form:
    print field.label_tag(attrs{'class':'Foo'})

我会在输出中看到 class='Foo'，但我没有看到从模板中添加 attrs 参数的方法 - 事实上，模板是专门为此设计的，不是吗?

I will see the class='Foo' in my output, but I don't see a way to add an attrs argument from the template - in fact, templates are designed specifically against that, no?

我的表单定义中有没有办法定义要在标签中显示的类?

Is there a way in my form definition to define the class to be displayed in the label?

在表单中，我可以执行以下操作来给输入一个类

In the form, I can do the following to give the inputs a class

self.fields['some_field'].widget.attrs['class'] = 'Foo'

我只需要让它输出 <label/> 的类.

I just need to have it output the class for the <label /> as well.

推荐答案

A 自定义模板标签 似乎是解决方案.自定义过滤器也可以，尽管它可能不那么优雅.但在这两种情况下，您都需要回退到自定义表单呈现.

A custom template tag seems to be the solution. A custom filter would also do, although it can be less elegant. But you would need to fall back to custom form rendering in both cases.

如果这是一项非常重要的任务；我将创建一个 Mixin，它允许我使用标签类注释表单字段，并使用这些类提供表单呈现方法.使以下代码有效:

If this is a task of high importance; I'd create a Mixin that allows me to annotate the form fields with label classes and supplies form rendering methods using those classes. So that the following code works:

{{ form.as_table_with_label_classes }}

但是我想问一下；你真的需要标签标签上的类吗?我的意思是 HTML 设计明智.绝对有必要在那里添加一个类吗?难道不能用一些 CSS 来解决，比如:

But I'd like to ask; Do you really need a class on the label tag? I mean HTML design-wise. Is it absolutely necessary to add a class in there? Couldn't it be solved with some CSS like:

encapsulating_selector label {
    some-attr: some-value;
}

我有时会使用 jQuery 来处理这种情况；如果它有效，它会改进页面，但如果它不起作用，它也不会是一场灾难.并尽可能精简 HTML 源代码.

I sometimes use jQuery for such cases where; it will improve the page if it works, but it won't be a disaster if it doesn't. And keep the HTML source as lean as possible.

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