谁能帮我在C#中获得输出

问题描述

PALINK-ID              PANELS
1.1                      10
                         20
************************************
1.2                      10
                         20
 -----------------------------
2.1                      10
                         20
                         30
--------------------------------------
2.2                      10
                         20
                         30  

我希望它在分裂.并计算面板中的元素并返回

输出:
1个具有2个面板
2具有3个面板(基于不同的值)

i want it to split at . and count the elements in panel and return it

output :
1 has 2 panels
2 has 3 panels(based distinct values)

推荐答案

public IEnumerable<Pair> CountThat(string data)
{
	var result = new List<Pair>();
	var lines = new List<string>(data.Split(new [] { Environment.NewLine }, StringSplitOptions.RemoveEmptyEntries));
	lines = lines.Where(x => !x.Contains(''-'') && !x.Contains(''*'')).ToList();

	double id = 0;
	foreach (var line in lines)
	{
		var item = line.Replace("\t", " "); // not sure if you''re using tab''s or spaces
		var sections = new List<string>(item.Split(new []{'' ''}, StringSplitOptions.RemoveEmptyEntries));
		if (sections.Count > 1)
		{
			if (!double.TryParse(sections[0], out id))
				id = 0;
			int panel;
			if (!int.TryParse(sections[1], out panel))
				panel = 0;

			if ((id != 0) && (panel != 0))
			{
				var pair = new Pair {Key = (int) id, Value = panel};
				if(!result.Contains(pair))
					result.Add(pair);
			}
		}
		else
		{
			int panel;
			if ((int.TryParse(sections[0], out panel)) &&
				(0 != id) )
			{
				var pair = new Pair {Key = (int) id, Value = panel};
				if (!result.Contains(pair))
					result.Add(pair);
			}
		}
	}

	return result;
}

然后查看结果，如:

then go over the result like:

foreach (var key in result.Select(x => x.Key).Distinct())
{
	int closure = key;
	int count = result.Count(x => x.Key == closure);
	Console.WriteLine(closure + " has " + count + " panels");
}

我以某种方式感到自己正在做作业....
如果这对您有用，请投票，接受答案并感到高兴.

此致AT

I somehow get the feeling that I''m doing your homework....
If this works for you, upvote it, accept the answer and be happy.

Regards, AT

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