链接:
https://www.luogu.org/problem/P3808
题意:
给定n个模式串和1个文本串,求有多少个模式串在文本串里出现过。
思路:
模板,
代码:
#include <iostream>
#include <cstdio>
#include <cstring>
#include <vector>
//#include <memory.h>
#include <queue>
#include <set>
#include <map>
#include <algorithm>
#include <math.h>
#include <stack>
#include <string>
#include <assert.h>
#include <iomanip>
#include <iostream>
#include <sstream>
#define MINF 0x3f3f3f3f
using namespace std;
typedef long long LL;
const int MAXN = 2e6+10;
struct Trie
{
int Next[26];
int End;
int Fail;
void Init()
{
memset(Next, 0, sizeof(Next));
End = Fail = 0;
}
}trie[MAXN];
int cnt, n;
char s[MAXN];
void Insert(char *t)
{
int len = strlen(t);
int p = 0;
for (int i = 0;i < len;i++)
{
if (trie[p].Next[t[i]-'a'] == 0)
{
trie[p].Next[t[i]-'a'] = ++cnt;
trie[cnt].Init();
}
p = trie[p].Next[t[i]-'a'];
}
trie[p].End++;
}
void BuildAC()
{
queue<int> que;
for (int i = 0;i < 26;i++)
{
if (trie[0].Next[i] != 0)
que.push(trie[0].Next[i]);
}
while (!que.empty())
{
int u = que.front();
que.pop();
for (int i = 0;i < 26;i++)
{
if (trie[u].Next[i])
{
trie[trie[u].Next[i]].Fail = trie[trie[u].Fail].Next[i];
que.push(trie[u].Next[i]);
}
else
trie[u].Next[i] = trie[trie[u].Fail].Next[i];
//压缩路径, 没有的点直接指向别的节点, 减少向上找的时间
}
}
}
int Query(char *qs)
{
int len = strlen(qs);
int p = 0, ans = 0;
for (int i = 0;i < len;i++)
{
p = trie[p].Next[qs[i]-'a'];
for (int j = p;j != 0 && trie[j].End != -1;j = trie[j].Fail)
{
//将所有能出现的匹配都跑一遍, 同时处理防止多跑.
ans += trie[j].End;
trie[j].End = -1;
}
}
return ans;
}
int main()
{
cnt = 0;
scanf("%d", &n);
trie[0].Init();
for (int i = 1;i <= n;i++)
{
scanf("%s", s);
Insert(s);
}
BuildAC();
scanf("%s", s);
printf("%d\n", Query(s));
return 0;
}