字符串以Google脚本开头

问题描述

我正在为我们正在进行的某些选举制作数据转换脚本.第一部分将所有名称更改为大写，脚本的这一部分工作正常.但是，我对脚本的第二部分有疑问.有些ID带有S，S123456，有些则没有S，123456.出于我的目的，我需要所有ID开头都没有s.当我在Google中运行此脚本时，它会返回

I am working on a data converting script for some elections we are doing. The first part changes all the names to upper case, and this part of the script works fine. However, I have a problem with the second part of the script. Some IDs will have an S, S123456, and some will not have an S, 123456. For my purposes I need all IDs to have no s at the beginning. When I run this script in Google it returns

有什么想法吗?

function convertResponseData(){
  var resultsInformation = SpreadsheetApp.openById('MySheetID').getSheetByName('Election Responses');
  var resultsDataRange = resultsInformation.getRange(1, 1, 2500, 6);
  var resultsData = resultsDataRange.getValues();
  for (var i = 0; i < resultsData.length; i++) {
    var row = resultsData[i];
    var resultsStudentNameLower = row[1];
    var resultsStudentID = row[2]
    var studentNameUpper = resultsStudentNameLower.toUpperCase()
    resultsInformation.getRange(i+1, 2).setValue(studentNameUpper)
    if (var n = resultsStudentID.startsWith("S")){
      var resultsStudentIDNoS = resultsStudentID.substring(1,20);
      resultsInformation.getRange(i+1, 3).setValue(resultsStudentIDNoS)
    }
  }
}

Google脚本不支持

推荐答案

startsWith().相反，您可以使用

resultsStudentID.indexOf("S") == 0

要检查字符串是否以"S"开头

To check if the string start starts with "S"

function convertResponseData(){
  var resultsInformation = SpreadsheetApp.openById('MySheetID').getSheetByName('Election Responses');
  var resultsDataRange = resultsInformation.getRange(1, 1, 2500, 6);
  var resultsData = resultsDataRange.getValues();
  for (var i = 0; i < resultsData.length; i++) {
    var row = resultsData[i];
    var resultsStudentNameLower = row[1];
    var resultsStudentID = row[2]
    var studentNameUpper = resultsStudentNameLower.toUpperCase()
    resultsInformation.getRange(i+1, 2).setValue(studentNameUpper)
    if (resultsStudentID.indexOf("S") == 0 ){
      var resultsStudentIDNoS = resultsStudentID.substring(1,20);  //You also do this resultsStudentID.substring(1) to get a substring from index 1 to end.
      resultsInformation.getRange(i+1, 3).setValue(resultsStudentIDNoS)
    }
  }
}

希望有帮助

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