填写重叠的圆形区域

问题描述

我有两个相交的圆，即使两个圆是透明的，我也希望使相交区域具有颜色.我以为我可以找到一些使用CSS mix-blend-mode 属性的方法，但是我没有成功.

I have two circles that intersect and I want to make the intersecting area have a color, even when the two circles are transparent. I thought I could find some way to do this with css mix-blend-mode property but I have had no success with it.

当然，我可以使圆形具有颜色并降低其不透明度，但是我希望它们是白色或透明的，其中只有重叠的区域才具有背景颜色.

Of course, I could make the circles have color and decrease their opacity, but I want them to be either white or transparent, where only the overlapped area gets background color.

我希望相交区域能够动态更改，因为鼠标将跟随一个圆圈.这是 codepen .

I want the intersecting area to be able to change dynamically because one circle will follow the mouse.Here is the codepen for that.

如果CSS具有某种技巧或者是否必须使用jquery，我不确定从哪里开始.

I'm not sure where to start on this, if css has some technique or if it will have to be done with jquery.

$(document).mousemove(function(e) {

  $('.cursor').eq(0).css({
    left: e.pageX - 25,
    top: e.pageY - 20
  });

  // circles
  var c1 = $('.cursor');
  var c2 = $('.circle');

  // radius
  var d1 = c1.outerWidth(true)/2;
  var d2 = c2.outerWidth(true)/2;

  // centers of first circle
  var x1 = c1.offset().left + c1.width()/2;
  var y1 = c1.offset().top + c1.height()/2;

  // centers of second circle
  var x2 = c2.offset().left + c2.width()/2;
  var y2 = c2.offset().top + c2.height()/2;

  var i1 = c2.find('.inter1');
  var i2 = c2.find('.inter2');
  var o = c1.find('.overlap');

  function calc() {
    var a = d2;
    var b = d1;
    var c = Math.sqrt((x1-x2)*(x1-x2)+(y1-y2)*(y1-y2));
    var d = (b*b+c*c-a*a)/(2*c);
    var h = Math.sqrt((b*b) - (d*d));
    if (d < 0 || $.isNumeric(h)) {
      c2.css('border-color', 'red');
    } else {
      c2.css('border-color', 'black');
    }
    var x3 = (x2-x1)*d/c + (y2-y1)*h/c +  x1;
    var y3 = (y2-y1)*d/c - (x2-x1)*h/c +  y1;
    var x4 = (x2-x1)*d/c - (y2-y1)*h/c +  x1;
    var y4 = (y2-y1)*d/c + (x2-x1)*h/c +  y1;

    if ($.isNumeric(h)) {
      i1.show();
      i2.show();
    } else {
      i1.hide();
      i2.hide();
    }
    i1.offset({ top: y3-5, left: x3-5});
    i2.offset({ top: y4-5, left: x4-5});
  } calc();


});

body {
  background: #fff;
}

.overlap {
  position: absolute;
  top: 0;
  right: 0;
  bottom: 0;
  left: 0;
  background: rgba(0, 0, 0, 0.5);
}

.cursor {
  height: 50px;
  width: 50px;
  border-radius: 50%;
  position: absolute;
  pointer-events: none;
  z-index: 999;
  border: 1px solid black;
  outline: 1px solid #c9d3ff;
  overflow: none;
}

.circle {
  border-radius: 50%;
  position: absolute;
  top: 50%;
  left: 50%;
  transform: translate(-50%, -50%);
  width: 200px;
  height: 200px;
  border: 1px solid black;
  outline: 1px solid #c9d3ff;
}

.circle::after,
.cursor::after {
  display: block;
  content: '';
  height: 1px;
  background: #c9d3ff;
  position: absolute;
  top: 50%;
  left: 0;
  right: 0;
}

.circle::before,
.cursor::before {
  display: block;
  content: '';
  width: 1px;
  background: #c9d3ff;
  position: absolute;
  left: 50%;
  top: 0;
  bottom: 0;
}

.inter {
  width: 10px;
  height: 10px;
  background: black;
  border-radius: 50%;
  position: absolute;
  display: none;
}

<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<div class="cursor">
</div>

<div class="circle">
  <div class="inter1 inter"></div>
  <div class="inter2 inter"></div>
  <div>

推荐答案

您可以采用的一种方法是在主圆内添加内光标"圆.根据鼠标的移动，如果有重叠的错觉，它将与主光标一起移动.

One way you can approach this is by adding a "inner-cursor" circle inside the main circle. Based on mouse movement it will move with the main cursor given the illusion of overlap.

在这种情况下，相交圆的背景颜色将无关紧要.同样，您也不必担心混合混合模式，因为内部光标具有背景色并且被隐藏了.仅当鼠标悬停在主圆上时才能查看.

In this case, the background color of the intersecting circles will not matter. Also, you do not have to worry about mix-blend-mode since the inner cursor has a background color and is hidden. It is only viewed if the mouse hovers over the main circle.

请参见以下示例:

$(document).mousemove(function(e) {

  // elements
  let cursor = $('.cursor');
  let innerCursor = $('.inner-cursor');
  let c2 = $('.circle');

  let pos = {
    left: e.pageX - 25,
    top: e.pageY - 20
  };
  cursor.css(pos);

  innerCursor.css({
    left: pos.left - c2.offset().left,
    top:  pos.top - c2.offset().top
  });

  // circles


  // radius
  var d1 = cursor.outerWidth(true) / 2;
  var d2 = c2.outerWidth(true) / 2;

  // centers of first circle
  var x1 = cursor.offset().left + cursor.width() / 2;
  var y1 = cursor.offset().top + cursor.height() / 2;

  // centers of second circle
  var x2 = c2.offset().left + c2.width() / 2;
  var y2 = c2.offset().top + c2.height() / 2;

  var i1 = c2.find('.inter1');
  var i2 = c2.find('.inter2');
  var o = cursor.find('.overlap');

  function calc() {
    var a = d2;
    var b = d1;
    var c = Math.sqrt((x1 - x2) * (x1 - x2) + (y1 - y2) * (y1 - y2));
    var d = (b * b + c * c - a * a) / (2 * c);
    var h = Math.sqrt((b * b) - (d * d));
    // console.log(a, b, c, d, h);
    if (d < 0 || $.isNumeric(h)) {
      c2.css('border-color', 'red');
    } else {
      c2.css('border-color', 'black');
    }
    var x3 = (x2 - x1) * d / c + (y2 - y1) * h / c + x1;
    var y3 = (y2 - y1) * d / c - (x2 - x1) * h / c + y1;
    var x4 = (x2 - x1) * d / c - (y2 - y1) * h / c + x1;
    var y4 = (y2 - y1) * d / c + (x2 - x1) * h / c + y1;

    if ($.isNumeric(h)) {
      i1.show();
      i2.show();
    } else {
      i1.hide();
      i2.hide();
    }
    i1.offset({
      top: y3 - 5,
      left: x3 - 5
    });
    i2.offset({
      top: y4 - 5,
      left: x4 - 5
    });
  }
  calc();

});

body {
  background: #fff;
}

.clip {
  display: inline-block;
  background: blue;
  height: 50px;
  width: 50px;
  border-radius: 50%;
  clip-path: ellipse(50px 50px at 50% 0%);
  position: absolute;
  left: 750px;
  top: 40px;
}

.cursor {
  left: 750px;
  top: 40px;
}

.cursor {
  height: 50px;
  width: 50px;
  border-radius: 50%;
  position: absolute;
  pointer-events: none;
  z-index: 999;
  border: 1px solid black;
  outline: 1px solid #c9d3ff;
  overflow: none;
  mix-blend-mode: multiply;
  background: rgba(100, 100, 100, 0.1);
}

.circle {
  background: rgba(100, 100, 100, 0.1);
  border-radius: 50%;
  position: absolute;
  top: 50%;
  left: 50%;
  transform: translate(-50%, -50%);
  width: 200px;
  height: 200px;
  border: 1px solid black;
  outline: 1px solid #c9d3ff;
  overflow: hidden;
}

.circle::after,
.cursor::after {
  display: block;
  content: '';
  height: 1px;
  background: #c9d3ff;
  position: absolute;
  top: 50%;
  left: 0;
  right: 0;
}

.circle::before,
.cursor::before {
  display: block;
  content: '';
  width: 1px;
  background: #c9d3ff;
  position: absolute;
  left: 50%;
  top: 0;
  bottom: 0;
}

.inter {
  width: 10px;
  height: 10px;
  background: black;
  border-radius: 50%;
  position: absolute;
  display: none;
}

.inner-cursor {
  height: 50px;
  width: 50px;
  border-radius: 50%;
  position: absolute;
  pointer-events: none;
  background: green;
  left: 50%;
  top: 50%;
}

<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<div class="cursor">

</div>
<span class="clip"></span>

<div class="circle">
  <div class='inner-cursor'></div>
  <div class="inter1 inter"></div>
  <div class="inter2 inter"></div>
</div>

这篇关于填写重叠的圆形区域的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！