PHP foreach循环来填充值的下拉列表，从一个数组的数组

问题描述

我有一个数组使用以下code创建的阵列。我试图通过得到这个循环和填充的下拉列表。

I have an array of an arrays created using the following code. I'm trying to get this to loop through and populate a dropdown list.

$names = $db->fetchAll("select `name` from `classes`");

这是什么是存储在$名称变量。

This is what is stored in the $names variable.

阵列（[0] =>阵列（[名称] =>网页设计）[1] =>阵列（[名称] =>
  艺术史）[2] =>阵列（[名称] =>健身房）[3] =>阵列（[名称] =>
  英文）[4] =>阵列（[名称] =>生物学）[5] =>阵列（[名称] =>
  三维动画）[6] =>阵列（[名称] =>技术光盘）[7] =>阵列（
  [名] =>数学）[8] =>阵列（[名称] =>舞蹈）[9] =>阵列（
  [名] =>视频制作）[10] =>阵列（[名称] =>首页EC）[11]
  =>阵列（[名称] =>政府）[12] =>阵列（[名称] =>物理））

我有这样的下拉列表中创建和它的工作，但它是在阵列中的每个值手codeD。我想修改此所以它的循环'到阵列中的所有结果来创建下拉列表。

I have this dropdown list created and it work, but it is hand coded for each value in the array. I want to modify this so it 'loops' through all results in the array to create the dropdown.

<label for="per1"></label>
<select name="per1" id="per1">
    <option selected="selected">Choose one</option>
    <option value="<?php echo $names[0]['name'];?>"><?php echo $names[0]['name'];?></option>
    <option value="<?php echo $names[1]['name'];?>"><?php echo $names[1]['name'];?></option>
    <option value="<?php echo $names[2]['name'];?>"><?php echo $names[2]['name'];?></option>
    <option value="<?php echo $names[3]['name'];?>"><?php echo $names[3]['name'];?></option>
    <option value="<?php echo $names[4]['name'];?>"><?php echo $names[4]['name'];?></option>
    <option value="<?php echo $names[5]['name'];?>"><?php echo $names[5]['name'];?></option>
    <option value="<?php echo $names[6]['name'];?>"><?php echo $names[6]['name'];?></option>
    <option value="<?php echo $names[7]['name'];?>"><?php echo $names[7]['name'];?></option>
    <option value="<?php echo $names[8]['name'];?>"><?php echo $names[8]['name'];?></option>
    <option value="<?php echo $names[9]['name'];?>"><?php echo $names[9]['name'];?></option>
    <option value="<?php echo $names[10]['name'];?>"><?php echo $names[10]['name'];?></option>
    <option value="<?php echo $names[11]['name'];?>"><?php echo $names[11]['name'];?></option>
    <option value="<?php echo $names[12]['name'];?>"><?php echo $names[12]['name'];?></option>
</select>

有人可以帮助？

推荐答案

该解决方案适用于目前的PHP版本。
使用foreach的简单情况：

This solution works for current PHP versions.Simple case of using a foreach:

<select name="per1" id="per1">
  <option selected="selected">Choose one</option>
  <?php
    foreach($names as $name) { ?>
      <option value="<?= $name['name'] ?>"><?= $name['name'] ?></option>
  <?php
    } ?>
</select>

该解决方案适用于旧的PHP版本。
使用foreach的简单情况：

This solution works for older PHP versions.Simple case of using a foreach:

<select name="per1" id="per1">
  <option selected="selected">Choose one</option>
  <?php
    foreach($names as $name) { ?>
      <option value="<?php echo $name['name'] ?>"><?php echo $name['name'] ?></option>
  <?php
    } ?>
</select>

这篇关于PHP foreach循环来填充值的下拉列表，从一个数组的数组的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！