问题描述
我正在使用Leaflet 1.0.0-rc.2 + e02b5c9.我知道默认值是渲染所有标记，折线...从屏幕上的经度-180到180，如下所示:
I am using Leaflet 1.0.0-rc.2+e02b5c9. I know the default is rendering all markers, polylines ... from longitude -180 to 180 as screen shot here:
但是，我想将地图显示为此时要显示的经度(这是日本和美国之间的中间海域):
However, I want to show the map as this longitude I want to show at this point (It is middle sea between Japan and US):
，但是您看到所有标记都未在右侧渲染.即使，如果我设置
but you see all the markers are not rendered on the right side. Even though, If i set
worldCopyJump: true
当我向右拖动时，所有标记都显示在右侧，但它们却消失在左侧，反之亦然.实际上，我希望它们同时出现.
when I drag to the right, all markers are appeared on the right but they are disappeared on the left and vice versa. Actually, I want they are appeared at the same time.
有任何解决办法吗?
推荐答案
只需确保标记的经度在0..360范围内，而不是在-180..180范围内. 看到一个有效的示例.
Just make sure that the longitudes of your markers are in the range 0..360 instead of in the range -180..180. See a working example.
即代替
L.marker([0,170]).addTo(map);
L.marker([0,-180]).addTo(map);
L.marker([0,-170]).addTo(map);
做类似的事情
L.marker([0,170]).addTo(map);
L.marker([0,180]).addTo(map);
L.marker([0,190]).addTo(map);
换句话说，如果经度小于零，则将其添加360.如果您打算一次过滤所有经度，则可能要使用L.Util.wrapNum(lng, [0,360], true).
In other words, if a longitude is smaller than zero, add 360 to it. You might want to use L.Util.wrapNum(lng, [0,360], true) instead, if you plan to filter all your longitudes at once.
这篇关于如何在180°子午线附近显示传单标记?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！