问题描述
我损坏了数据库.在命令行中我输入
I have corrupted database. In commandline I typed
PRAGMA integrity_check
和sqlite返回
On tree page 441 cell 17: Rowid 205 out of order (min less than parent max of 12258)
On tree page 26 cell 12: 2nd reference to page 441
On tree page 26 cell 12: Child page depth differs
On tree page 26 cell 13: Child page depth differs
Page 65 is never used
Page 66 is never used
wrong # of entries in index sqlite_autoindex_TBL_1
在我的 c 程序中输入
In my c program I typed
sqlite3 *glbDBHandle;
sqlite3_open(DB_FILE, &glbDBHandle);
int result=sqlite3_exec(glbDBHandle, "PRAGMA integrity_check", 0, 0, 0);
此代码始终返回 0，数据库损坏且健康.
this code returns always 0 with broken and healthy databases.
我应该如何在 C 中使用PRAGMA完整性检查"?或者我怎么知道我的 sqlite 数据库坏了?
How should I use "PRAGMA integrity_check" in C ? Or how can I know my sqlite database is broken ?
推荐答案
PRAGMAintegrity_check行为类似于在单行中返回结果的 SELECT 查询.要使用 sqlite3_exec 读取结果，您需要使用回调.
PRAGMA integrity_check behaves like a SELECT query that returns results in a single row.To read the results with sqlite3_exec, you need to use a callback.
请注意，PRAGMAintegrity_check 不能保证找到所有错误，因此您只能使用它来检查损坏的数据库，而不是检查健康的数据库.
Please note that PRAGMA integrity_check is not guaranteed to find all errors, so you can use it only to check for broken databases, not for healthy databases.
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