本文介绍了在断言malloc.c:2453的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我有以下计划,试图来标记一个字符串(基于空间),并将其写入一个char **数组。
I have the following program which tries to tokenize a string (based on space) and write it into a char ** array.
#include <stdio.h>
#include <stdlib.h>
#define len 180
void tokenize(char *str, char **tokens)
{
int l = 0, index = 0;
int i = 0;
int str_i;
int tok_i;
while(*str) {
if (*str == ' ') {
tokens[i] = malloc(sizeof(char) * l+1);
if (tokens[i] == NULL) return;
tok_i = 0;
for (str_i=index-len ; str_i<index ; str_i++) {
tokens[i][tok_i] = str[str_i];
tok_i++;
}
tokens[i][tok_i] = '\0';
tokens[i++] = NULL;
l = 0;
index++;
}
str++;
l++;
index++;
}
return;
}
int main()
{
char str[len] = "this is a test string";
char **tokens = malloc(100 * sizeof(char *));
if (str == NULL || tokens == NULL)
return 1;
printf("input string: %s\n", str);
tokenize(str, tokens);
return 0;
}
以上程序编译罚款,但在执行的时候,我得到了 malloc.c
$ gcc -ggdb -Wall prog.c
$ ./a.out
input string: this is a test string
a.out: malloc.c:2453: sYSMALLOc: Assertion `(old_top == (((mbinptr) (((char *) &((av)->bins[((1) - 1) * 2])) - __builtin_offsetof (struct malloc_chunk, fd)))) && old_size == 0) || ((unsigned long) (old_size) >= (unsigned long)((((__builtin_offsetof (struct malloc_chunk, fd_nextsize))+((2 * (sizeof(size_t))) - 1)) & ~((2 * (sizeof(size_t))) - 1))) && ((old_top)->size & 0x1) && ((unsigned long)old_end & pagemask) == 0)' failed.
Aborted (core dumped)
$
和堆栈跟踪显示以下内容:
And the stack trace shows the following:
(gdb) bt
#0 0x0000003b28036285 in raise () from /lib64/libc.so.6
#1 0x0000003b28037b9b in abort () from /lib64/libc.so.6
#2 0x0000003b2807d37d in __malloc_assert () from /lib64/libc.so.6
#3 0x0000003b28080c37 in _int_malloc () from /lib64/libc.so.6
#4 0x0000003b28082595 in malloc () from /lib64/libc.so.6
#5 0x000000000040055f in tokenize (str=0x7fffffffe017 " a test string", tokens=0x601010) at prog.c:15
#6 0x00000000004006de in main () at prog.c:46
(gdb)
如何调试呢?任何想法将是非常美联社preciated。
How do I debug this? Any idea would be highly appreciated.
推荐答案
在您的for循环
for (str_i=index-len ; str_i<index ; str_i++)
STR_I是一个负数。
str_i is a negative number.
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