如何完全反汇编Python源代码

问题描述

我一直在使用 dis 库来反汇编一些Python源代码，但是我发现这并没有递归为函数或类：

I have been playing with the dis library to disassemble some Python source code, but I see that this does not recurse into functions or classes:

import dis

source_py = "test.py"

with open(source_py) as f_source:
    source_code = f_source.read()

byte_code = compile(source_code, source_py, "exec")
dis.dis(byte_code)

我所看到的都是以下条目：

All I see are entries such as:

 54         456 LOAD_CONST              63 (<code object foo at 022C9458, file "test.py", line 54>)
            459 MAKE_FUNCTION            0
            462 STORE_NAME              20 (foo)

如果源文件具有功能 foo（），我显然可以在源文件中添加以下内容：

If the source file had a function foo(), I could obviously add something like the following to the sourcefile:

dis.dis(foo)

我不知道如何在不更改源文件的情况下执行此操作并执行它。我希望能够从编译后的 byte_code 中提取相关的字节，并将其传递给 dis.dis（）

I cannot figure out how to do this without changing the source file and executing it. I would like to be able to extract the pertinent bytes from the compiled byte_code and pass them to dis.dis().

def sub_byte_code(byte_code, function_or_class_name):
    sub_byte_code = xxxxxx
    dis.dis(sub_byte_code)

我已经考虑过包装源代码并执行 dis.dis（）如下，但我不想执行该脚本：

I have considered wrapping the source code and executing dis.dis() as follows but I do not wish to execute the script:

source_code_dis = "import dis\n%s\ndis.dis(foo)\n" % (source_code)
exec(source_code_dis)

也许有把戏吗？例如 dis.dis（byte_code，recurse = True）

推荐答案

导入文件作为模块，然后在该模块上调用 dis.dis（）。

Import the file as a module and call dis.dis() on that module.

import dis
import test

dis.dis(test)

您也可以从命令行执行此操作：

You can also do this from the command-line:

python -m dis test.py

引用的文档：

Quoting from the documentation for dis.dis:

编辑：从python 3.7开始， dis.dis 是递归的。

Edit: As of python 3.7, dis.dis is recursive.

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