将限制关键字用于2d数组函数参数的语法是什么?

问题描述

我在主函数中声明了一个数组:float A[n][n];

I have an array declared in my main function:float A[n][n];

我的目标是使用restrict关键字将其传递给函数:void func(int n, float restrict A[][n])

My goal is to pass it to a function with the restrict keyword:void func(int n, float restrict A[][n])

我尝试了上面的语法，但是我没有获得期望的运行时间优化.我也看到了1d数组的这种语法:void func(int n, float A[restrict])

I tried the syntax above, but I am not getting the optimization in running time that I am expecting. I have also seen this syntax for 1d arrays:void func(int n, float A[restrict])

推荐答案

可以限制指针.以下所有形式都是等效的:

The pointer can be restrict. All below forms are equivalent:

void func(int n, float A[restrict n][n]);
void func(int n, float A[restrict][n]);
void func(int n, float (* restrict A)[n]);

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