健壮的方式递归地提交一个子模块

健壮的方式递归地提交一个子模块

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问题描述

有一个强大的方法来执行递归深度优先 git submodule foreach 命令?我使用 foreach --recursive 命令来完成这项工作,除了它是宽度优先。这是一个问题,因为如果我有以下结构:


  • A

    • B


  • C



提交全部三个, foreach --recursive add -A&& git commit ... 会碰到A,B,C,如果我想让supermodule在那时捕获B的提交,这是有问题的。

我从2008年发现了,但是它看起来并不像任何建议的功能(1.7.9.5)。



我写了一个小的bash函数来做这件事(原谅速记命名):

 函数git-sfed(){git submodule foreachgit submodule foreach'$ *'&& $ *; } 

使用下面这个fanciful命令测试它似乎是可行的:

  git-sfed'python -cimport sys; print sys.argv$ path'

这个命令看起来很健壮吗,还是还有其他常用的现有方法吗?

解决方案

您可以试试这个

  git submodule foreach --recursive | tail -r | sed's /进入//'| xargs -I%cd%; git add -A \& git commit 

这个列表(递归地)所有子模块,然后颠倒列表 tail -r 这样你就可以按照你想要的顺序获得目录(子优先),进入目录并做任何你想要的内容。


Is there a robust way to do a recursive depth-first git submodule foreach command? I am using the foreach --recursive command which does the job, except it is breadth-first. This is a problem because if I have the following structure:

  • A
    • B
  • C

And I have commits in all three, a foreach --recursive add -A && git commit ... will hit A, B, C, which is problematic if I want the supermodule to capture the commits of B at that time.

I found this discussion from 2008, but it does not look like any of the suggested features are in the current version of Git that I have (1.7.9.5).

I wrote a small bash function to do this (excuse the shorthand naming):

function git-sfed() { git submodule foreach "git submodule foreach '$*' && $*"; }

And testing it with the following fanciful command seems to work:

git-sfed 'python -c "import sys; print sys.argv" $path'

Does this command seem robust, or are there other common existing methods?

解决方案

You can try this

git submodule  foreach --recursive  |  tail  -r | sed 's/Entering//' | xargs -I% cd % ; git add -A \& git commit

This list (recursively) all the submodules , then reverse the list, tail -r so you get the directories in the order you want (child first), enter the directory and do what ever you want in it.

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09-03 03:28