Flutter-有没有办法仅使用IconButton(不创建应用栏)来打开抽屉?

问题描述

我正在尝试使用可以在应用页面上打开抽屉的IconButton，因此，当我点击图标按钮时，我希望看到抽屉.我一直在寻找一种在线执行此操作的方法，但似乎只有两种解决方案:我可以使用应用程序栏将IconButton放入其中，也可以尝试浮动操作按钮.但是它们不是我想要的，我只希望使用IconButton打开抽屉.有可能吗?

I'm trying to use the IconButton that can open the drawer on my app page, so when I tap the icon button, I expect to see the drawer. I've been looking up a way to do so online, but seemed like there're only two solutions: I can either use the appbar to put the IconButton in, or I can try the floating action button. But they're not what I'm looking for, I want just the IconButton to open the drawer. Is it possible do it?

推荐答案

是的，您可以通过 IconButton 轻松打开抽屉，而无需使用 appBar .您需要像使用_scaffoldKey一样使用Key并使用 _scaffoldKey.currentState.openDrawer()方法在 IconButton 小部件中打开抽屉.

Yes, you can easily open the drawer through IconButton without using appBar.You need to use Key like I had used _scaffoldKey and use _scaffoldKey.currentState.openDrawer() method to open the drawer in IconButton widget.

class HomeState extends StatelessWidget {

final GlobalKey<ScaffoldState> _scaffoldKey =  GlobalKey<ScaffoldState>();

 @override
Widget build(BuildContext context) {

return Scaffold(
  key: _scaffoldKey,
         drawer: Drawer(
      child: ListView(
        children: <Widget>[
          ListTile(
            title: Text("Ttem 1"),
            trailing: Icon(Icons.arrow_forward),
          ),
          ListTile(
            title: Text("Item 2"),
            trailing: Icon(Icons.arrow_forward),
          ),
        ],
      ),
    ),
        body: ListView(
         children:[

    Container(
              margin: EdgeInsets.only(left: 15.0,top:100.0),
              child: IconButton(
                icon: Icon(Icons.menu),
                onPressed: () {
                  _scaffoldKey.currentState.openDrawer();
                },

              ),
            ),
            ]
        ),
            );}


   }

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