使用预定义的过滤器过滤android ListView

问题描述

我刚接触Android.我想为ListView实现预定义的过滤器.我的ListView将包含数字，并且会有一个过滤器图标，单击该图标应显示显示奇数"，显示偶数"和显示全部"之类的选项.

I am pretty new to Android. I want to implement predefined filters for a ListView. My ListView will contain numbers and there would be a Filter icon which on click should show options like "Show odd", "Show even" and "Show all".

我的问题是如何在单击过滤器"图标时显示弹出对话框?如果使用一个简单的弹出对话框实现了此目的，那么如何使用选定的选项过滤ListView?我尝试搜索Android论坛，但他们主要谈论的是文本过滤器.指向具有类似问题陈述的文章的指针也可能会有所帮助.

My question is how to display a popup dialog on click of the Filter icon? If that is achieved using a simple popup dialog, then how do I filter the ListView with the option selected? I tried searching Android forums but they speak mainly about text filters. Pointers to articles having similar problem statement could also help.

推荐答案

您可以实现过滤器是这样的:

class MyFilter extends Filter {

    private final MyAdapter myAdapter;

    public MyFilter(MyAdapter myAdapter) {
        this.myAdapter = myAdapter;
    }

    @Override
    protected Filter.FilterResults performFiltering(CharSequence constraint) {
        FilterResults results = new FilterResults();
        if (constraint == null || constraint.length() == 0) {
    // unfiltered: show all
            results.values = myAdapter.getOriginalList();
            results.count = myAdapter.getOriginalList().size();
        } else {
    // filtered
            List<Integer> newWorkingList = new ArrayList<>();
            if (constraint.equals('1')) {
    // odd
                for (Integer integer : myAdapter.getOriginalList()) {
                    if (integer % 2 == 1) {
                            newWorkingList.add(integer);
                    }
                }
            } else if (constraint.equals('2')) {
    // even
                for (Integer integer : myAdapter.getOriginalList()) {
                    if (integer % 2 == 0) {
                        newWorkingList.add(integer);
                    }
                }
            }
            results.values = newWorkingList;
            results.count = newWorkingList.size();
        }
        return results;
    }

    @Override
    protected void publishResults(CharSequence constraint, FilterResults results) {
        myAdapter.setFilteredList((List<String>) results.values);
        if (results.count == 0) {
            myAdapter.notifyDataSetInvalidated();
        } else {
            myAdapter.notifyDataSetChanged();
        }
    }
}

在适配器类中，您必须进行以下更改:

In your adapter class you have to make changes similar to these:

public class MyAdapter extends ArrayAdapter<Integer> implements Filterable

    private MyFilter MyFilter;

    @Override
    public Filter getFilter() {
        if (myFilter == null) {
            myFilter = new myFilter(this);
        }
        return myFilter;
    }

并且您必须为原始列表添加一个setter.

And you have to add a setter for your original list.

最后，在弹出对话框的侦听器中，您必须根据用户的选择添加以下行:

And, finally, in the listener of your popup dialog you have to add these lines depending on the user's choice:

myAdapter.getFilter().filter(null);
myAdapter.getFilter().filter('1');
myAdapter.getFilter().filter('2');

这篇关于使用预定义的过滤器过滤android ListView的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！