从RES / XML在Android开放XML文件

问题描述

我创建了打开一个看起来像这样的XML文件Java应用程序：

I created a Java application which opens an xml file that looks something like this:

<AnimalTree>
  <animal>
    <mammal>canine</mammal>
    <color>blue</color>
  </animal>
  <!-- ... -->
</AnimalTree>

我可以使用打开它：

And I can open it using:

File fXmlFile = getResources.getXml("res/xml/data.xml");
DocumentBuilderFactory dbFactory = DocumentBuilderFactory.newInstance();
DocumentBuilder dBuilder = dbFactory.newDocumentBuilder();
Document doc = dBuilder.parse(fXmlFile);
doc.getDocumentElement().normalize();
NodeList animalNodes = doc.getElementsByTagName("animal");

然后，我可以简单地创建一个节点，对象推入一个ListArray，然后做我想做的对象为通过ListArray我循环。

Then I can simply create a node, push the object into a ListArray, then do what I want with the objects as I loop through the ListArray.

for (int temp = 0; temp < animalNodes.getLength(); temp++) {
Node nNode = animalNodes.item(temp);
if (nNode.getNodeType() == Node.ELEMENT_NODE) {
Element eElement = (Element) nNode;
question thisAnimal = new animal();
thisAnimal.mammal = getTagValue("mammal",eElement);
// ...

平原和简单！现在只有在Android的我不能简单地读取文件 RES / XML / data.xml中，因为文件（）; 要求字符串不是整数（ID）。这是我很失落。有一些办法可以让文件（）; 打开文件，或者这是不可能的，而无需使用的SAXParser 或 XPP ？ （这两个我实在无法理解，不管我怎么努力。）
如果我被迫使用这些方法，可以有人告诉我一些简单的code类似于我的例子？

Plain and simple! Now only, in Android I cannot simply read the file "res/xml/data.xml" because "File();" requires a String not an integer (id). This is where I am lost. Is there some way I can make "File();" open the file, or is this impossible without using SAXparser or XPP? (both of which I really cannot understand, no matter how hard I try.)
If I am forced to use those methods, can someone show me some simple code analogous to my example?

推荐答案

如果它在资源树，它会得到分配给它的ID，这样你就可以打开一个流，它与openRawResource功能：

If it's in the resource tree, it'll get an ID assigned to it, so you can open a stream to it with the openRawResource function:

的InputStream是= context.getResources（）openRawResource（R.xml.data）;

对于使用XML在Android的工作，此链接ibm.com 是令人难以置信彻底。

As for working with XML in Android, this link on ibm.com is incredibly thorough.

请参阅清单9.基于DOM实现饲料解析器的该链接。

一旦你的输入流（上图），你可以把它传递给的DocumentBuilder实例：

Once you have the input stream (above) you can pass it to an instance of DocumentBuilder:

DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
DocumentBuilder builder = factory.newDocumentBuilder();
Document dom = builder.parse(this.getInputStream());
Element root = dom.getDocumentElement();
NodeList items = root.getElementsByTagName("TheTagYouWant");

请记住，我没有这样做个人 - 我假设由IBM工作提供的code。

Keep in mind, I haven't done this personally -- I'm assuming the code provided by IBM works.

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