Pygame:重新调整像素大小

问题描述

使用 pygame，我创建了一个 20x20 像素的窗口并添加了一个 2x2 像素的矩形.当我运行程序时，窗口大小非常小，几乎看不到矩形.如何在保持像素数不变的同时增加窗口大小，即增加像素大小?我知道这个类似的问题，但讨论了一个更复杂的案例.>

With pygame, I created a 20x20 pixel window and added a 2x2 pixel rectangle.When I run the program, the window size is super small and I can barely see the rectangle. How can I increase the window size whilst keeping the number of pixels constant, i.e. increase the pixel size? I am aware of this similar question, but there a somewhat more complicated case is discussed.

import pygame
screen_width, screen_height = 20, 20
x, y = 10, 10
rect_width, rect_height = 2, 2
vel = 2
black = (0, 0, 0)
white = (255, 255, 255)
pygame.init()
win = pygame.display.set_mode((screen_width, screen_height))
run = True
while run:
    pygame.time.delay(100)
    for event in pygame.event.get():
        if event.type == pygame.QUIT:
            run = False
    win.fill(black)
    pygame.draw.rect(win, white, (x, y, rect_width, rect_height))
    pygame.display.update()
pygame.quit()

推荐答案

不要直接绘制到屏幕上，而是绘制到另一个Surface.

Don't draw directly to the screen, but to another Surface.

然后将新的 Surface 缩放到屏幕的大小并将其 blit 到真实的屏幕表面上.

Then scale that new Surface to the size of the screen and blit it onto the real screen surface.

这是一个例子:

import pygame
screen_width, screen_height = 20, 20

scaling_factor = 6

x, y = 10, 10
rect_width, rect_height = 2, 2
vel = 2
black = (0, 0, 0)
white = (255, 255, 255)
pygame.init()
win = pygame.display.set_mode((screen_width*scaling_factor, screen_height*scaling_factor))

screen = pygame.Surface((screen_width, screen_height))

run = True
while run:
    pygame.time.delay(100)
    for event in pygame.event.get():
        if event.type == pygame.QUIT:
            run = False

    screen.fill(black)
    pygame.draw.rect(screen, white, (x, y, rect_width, rect_height))

    win.blit(pygame.transform.scale(screen, win.get_rect().size), (0, 0))
    pygame.display.update()
pygame.quit()

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