明确解决的意向动态广播接收器

问题描述

我是新来的Andr​​oid，并试图了解应用程序之间的通信。

i am new to Android and trying to understand the communication between apps.

我想写3可以相互通信的小应用程序。如果您想发送一条消息给大家，你只需要使用一个隐含的播放。

I am trying to write 3 little apps which can communicate with each other. If you want to sent a message to everybody you just use an implicit broadcast.

隐含的意图 intent.setAction（com.example.myChatMessage）

如果你想解决只有1 specifc接收我做到了以

if you want to adress only 1 specifc receiver i did it with

explicite意图 intent.setComponent（com.example.test.android.broadcastreceiver.bcom.example.test.android.broadcastreceiver.b.myBroadcastReceiver）

explicite Intentintent.setComponent("com.example.test.android.broadcastreceiver.b","com.example.test.android.broadcastreceiver.b.myBroadcastReceiver")

这工作，当广播接收器是一个独立的类，并在AndroidManifest.xml中定义。

this works, when the broadcast receiver is a seperate class and defined in the AndroidManifest.xml.

我的提问：是有可能的明确的联系地址一dynamicall注册的广播接收器的

package com.example.test.android.broadcastreceiver.b;

public class MainActivity extends Activity {

private final IntentFilter intentfilter = new IntentFilter("com.example.myChatMessage");
private myBroadcastReceiver broadcastreceiver;

@Override
public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);
    broadcastreceiver = new myBroadcastReceiver();
    registerReceiver(broadcastreceiver, intentfilter);
}

public static class myBroadcastReceiver extends BroadcastReceiver{
    @Override
    public void onReceive(Context context, Intent intent) {
        String message = intent.getStringExtra("message");
        Log.d("message", "B received: "+message);
    }
}
}

它接收所有隐式广播，但没有明确的关系 - 我不知道烫ADRESS它。你能帮助我吗？

It receives all implicit broadcasts but no explicit one - i don't know hot to adress it. Can you help me?

推荐答案

它似乎不是可以发送一个明确的意图动态注册的广播接收器。注册在AndroidManifest.xml中的接收器是唯一的办法。

It does not appear possible to send an explicit intent to a dynamically registered broadcast receiver. Registering the receiver in AndroidManifest.xml is the only way.

如果你动态地注册一个BroadcastReceiver - 通过调用Context.registerReceiver（） - 你提供一个BroadcastReceiver的实例的......如果您尝试通过命名类的BroadcastReceiver送的意图接收器，它永远不会被传递.. Android系统不会你申报的类，你注册的BroadcastReceiver实例的意图相匹配。

来源：http://onemikro2nd.blogspot.com/2013/09/darker-corners-of-android.html

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