本文介绍了连接与SQLite数据库Android应用程序时无法找到表名的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我是新至Android编程,请帮助我。我已经使用SQLite浏览器创建的数据库中,我尝试连接我的应用程序使用该数据库文件,但它不工作,错误日志中说,没有这样的表:datasaya。怎么会发生这种事,而在我创建的数据库,只有1台。
I am new to android programming so please help me. I have created database using SQLite browser, I am try to connecting my app with this database file, but it is not working, the error log say that "no such table : datasaya". How could this happen while in the database I created there is only 1 table.
这是我的sqlite的辅助类:
public class SQLiteHelper extends SQLiteOpenHelper {
private static String DB_PATH="/data/data/com.example.latihandbsqlite/databases/";
private static String DB_NAME = "cekdatabase.sqlite";
private static int VERSION =1;
private SQLiteDatabase myDataBase;
private final Context myContext;
public SQLiteHelper(Context context) {
super(context, DB_NAME, null, VERSION);
myContext = context;
try {
createDatabase();
} catch (IOException ioe) {
throw new Error("Unable to create database");
}
}
public void createDatabase() throws IOException {
boolean dbExist = checkDataBase();
if (dbExist) {
System.out.println("DB EXIST");
} else {
this.getReadableDatabase();
this.close();
copyDataBase();
}
}
private void copyDataBase() throws IOException {
InputStream myInput = myContext.getAssets().open(DB_NAME);
String outFileName = DB_PATH + DB_NAME;
OutputStream myOutput = new FileOutputStream(outFileName);
byte[] buffer = new byte[1024];
int length;
while ((length = myInput.read(buffer)) > 0) {
myOutput.write(buffer, 0, length);
}
myOutput.flush();
myOutput.close();
myInput.close();
}
private boolean checkDataBase() {
SQLiteDatabase checkDB = null;
try {
String myPath = DB_PATH + DB_NAME;
checkDB = SQLiteDatabase.openDatabase(myPath,
null, SQLiteDatabase.OPEN_READONLY);
} catch (SQLiteException e) {
System.out.println("Database does't exist yet.");
}
if (checkDB != null) {
checkDB.close(); }
return checkDB != null ? true : false;
}
@Override
public synchronized void close() {
if (myDataBase != null) myDataBase.close();
super.close();
} @Override
public void onCreate(SQLiteDatabase arg0) {
} @Override
public void onUpgrade(SQLiteDatabase db, int oldVersion, int newVersion) {
}
}
这是我的SQLiteConnector类:
public class SQLiteConnector {
private SQLiteDatabase database;
private SQLiteHelper sqlHelper;
private Cursor cursor;
private static final String TABLE_RECORD = "datasaya";
public SQLiteConnector(Context context) {
sqlHelper = new SQLiteHelper(context);
} // Getting All records
public List<String> getAllRecord() {
List<String> namagambar = new ArrayList<String>();
String selectQuery = "SELECT * FROM " + TABLE_RECORD;
database = sqlHelper.getReadableDatabase();
cursor = database.rawQuery(selectQuery, null);
if (cursor.moveToFirst()) {
do {
namagambar.add(cursor.getString(1));
} while (cursor.moveToNext());
}
database.close();
return namagambar;
}
}
我怎样才能解决这个问题呢?
How can i resolve this problem ?
推荐答案
删除你的数据库的名称的点。
发件人: cekdatabase.sqlite
以: cekdatabase
Remove the point of the name of your database.From: cekdatabase.sqlite
to: cekdatabase
.
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