本文介绍了如何在Oracle中将以毫秒为单位的时间戳转换为日期的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！
问题描述
我在Oracle中将 MSSTAMP 设置为毫秒时间戳"，格式:1483228800000.如何将毫秒时间戳转换为日期格式"YYYY-MM"，以获取完成计数前几年的每月行数.
I have MSSTAMP as "timestamp with milliseconds" in Oracle, format: 1483228800000. How can I cast that milliseconds timestamp into a date format "YYYY-MM", in order to get count of FINISHED rows per month for previous years.
我尝试了TO_DATE，CAST和TO_CHAR的不同变体-但无法正常工作.
I have tried different variations of TO_DATE, CAST, TO_CHAR - but I'm unable to get this working.
select
count(*) "EVENTS",
TO_DATE(MSSTAMP, 'YYYY-MM') "FINISHED_MONTH"
from
DB_TABLE
where
MSSTAMP < '1483228800000'
and
STATUS in ('FINISHED')
group by
FINISHED_MONTH ASC
推荐答案
如果您只需要将自纪元以来的毫秒数转换为日期，那么:
If you just need to convert from milliseconds since epoch to a date, then:
SELECT TIMESTAMP '1970-01-01 00:00:00.000'
+ NUMTODSINTERVAL( 1483228800000 / 1000, 'SECOND' )
AS TIME
FROM DUAL
哪个输出:
TIME
-----------------------
2017-01-01 00:00:00.000
只需要年份-月，然后使用TRUNC( timestamp, 'MM' )或TO_CHAR( timestamp, 'YYYY-MM' ).
It you just want the year-month then use TRUNC( timestamp, 'MM' ) or TO_CHAR( timestamp, 'YYYY-MM' ).
如果您需要处理leap秒，则可以创建一个实用程序包，该实用程序包将调整时期以考虑到这个:
If you need to handle leap seconds then you can create a utility package that will adjust the epoch time to account for this:
CREATE OR REPLACE PACKAGE time_utils
IS
FUNCTION milliseconds_since_epoch(
in_datetime IN TIMESTAMP,
in_epoch IN TIMESTAMP DEFAULT TIMESTAMP '1970-01-01 00:00:00'
) RETURN NUMBER;
FUNCTION milliseconds_epoch_to_ts (
in_milliseconds IN NUMBER,
in_epoch IN TIMESTAMP DEFAULT TIMESTAMP '1970-01-01 00:00:00'
) RETURN TIMESTAMP;
END;
/
SHOW ERRORS;
CREATE OR REPLACE PACKAGE BODY time_utils
IS
-- List of the seconds immediately following leap seconds:
leap_seconds CONSTANT SYS.ODCIDATELIST := SYS.ODCIDATELIST(
DATE '1972-07-01',
DATE '1973-01-01',
DATE '1974-01-01',
DATE '1975-01-01',
DATE '1976-01-01',
DATE '1977-01-01',
DATE '1978-01-01',
DATE '1979-01-01',
DATE '1980-01-01',
DATE '1981-07-01',
DATE '1982-07-01',
DATE '1983-07-01',
DATE '1985-07-01',
DATE '1988-01-01',
DATE '1990-01-01',
DATE '1991-01-01',
DATE '1992-07-01',
DATE '1993-07-01',
DATE '1994-07-01',
DATE '1996-01-01',
DATE '1997-07-01',
DATE '1999-01-01',
DATE '2006-01-01',
DATE '2009-01-01',
DATE '2012-07-01',
DATE '2015-07-01',
DATE '2016-01-01'
);
HOURS_PER_DAY CONSTANT BINARY_INTEGER := 24;
MINUTES_PER_HOUR CONSTANT BINARY_INTEGER := 60;
SECONDS_PER_MINUTE CONSTANT BINARY_INTEGER := 60;
MILLISECONDS_PER_SECOND CONSTANT BINARY_INTEGER := 1000;
MINUTES_PER_DAY CONSTANT BINARY_INTEGER := HOURS_PER_DAY * MINUTES_PER_HOUR;
SECONDS_PER_DAY CONSTANT BINARY_INTEGER := MINUTES_PER_DAY * SECONDS_PER_MINUTE;
MILLISECONDS_PER_MINUTE CONSTANT BINARY_INTEGER := SECONDS_PER_MINUTE * MILLISECONDS_PER_SECOND;
MILLISECONDS_PER_HOUR CONSTANT BINARY_INTEGER := MINUTES_PER_HOUR * MILLISECONDS_PER_MINUTE;
MILLISECONDS_PER_DAY CONSTANT BINARY_INTEGER := HOURS_PER_DAY * MILLISECONDS_PER_HOUR;
FUNCTION milliseconds_since_epoch(
in_datetime IN TIMESTAMP,
in_epoch IN TIMESTAMP DEFAULT TIMESTAMP '1970-01-01 00:00:00'
) RETURN NUMBER
IS
p_leap_milliseconds BINARY_INTEGER := 0;
p_diff INTERVAL DAY(9) TO SECOND(3);
BEGIN
IF in_datetime IS NULL OR in_epoch IS NULL THEN
RETURN NULL;
END IF;
p_diff := in_datetime - in_epoch;
IF in_datetime >= in_epoch THEN
FOR i IN 1 .. leap_seconds.COUNT LOOP
EXIT WHEN in_datetime < leap_seconds(i);
IF in_epoch < leap_seconds(i) THEN
p_leap_milliseconds := p_leap_milliseconds + MILLISECONDS_PER_SECOND;
END IF;
END LOOP;
ELSE
FOR i IN REVERSE 1 .. leap_seconds.COUNT LOOP
EXIT WHEN in_datetime > leap_seconds(i);
IF in_epoch > leap_seconds(i) THEN
p_leap_milliseconds := p_leap_milliseconds - MILLISECONDS_PER_SECOND;
END IF;
END LOOP;
END IF;
RETURN MILLISECONDS_PER_SECOND * EXTRACT( SECOND FROM p_diff )
+ MILLISECONDS_PER_MINUTE * EXTRACT( MINUTE FROM p_diff )
+ MILLISECONDS_PER_HOUR * EXTRACT( HOUR FROM p_diff )
+ MILLISECONDS_PER_DAY * EXTRACT( DAY FROM p_diff )
+ p_leap_milliseconds;
END milliseconds_since_epoch;
FUNCTION milliseconds_epoch_to_ts(
in_milliseconds IN NUMBER,
in_epoch IN TIMESTAMP DEFAULT TIMESTAMP '1970-01-01 00:00:00'
) RETURN TIMESTAMP
IS
p_datetime TIMESTAMP;
BEGIN
IF in_milliseconds IS NULL OR in_epoch IS NULL THEN
RETURN NULL;
END IF;
p_datetime := in_epoch
+ NUMTODSINTERVAL( in_milliseconds / MILLISECONDS_PER_SECOND, 'SECOND' );
IF p_datetime >= in_epoch THEN
FOR i IN 1 .. leap_seconds.COUNT LOOP
EXIT WHEN p_datetime < leap_seconds(i);
IF in_epoch < leap_seconds(i) THEN
p_datetime := p_datetime - INTERVAL '1' SECOND;
END IF;
END LOOP;
ELSE
FOR i IN REVERSE 1 .. leap_seconds.COUNT LOOP
EXIT WHEN p_datetime > leap_seconds(i);
IF in_epoch > leap_seconds(i) THEN
p_datetime := p_datetime + INTERVAL '1' SECOND;
END IF;
END LOOP;
END IF;
RETURN p_datetime;
END milliseconds_epoch_to_ts;
END;
/
SHOW ERRORS;
然后您可以执行以下操作:
Then you can do:
SELECT TIME_UTILS.milliseconds_epoch_to_ts(
in_milliseconds => 1483228800000,
in_epoch => TIMESTAMP '1970-00-00 00:00:00.000'
) AS time
FROM DUAL;
并获得输出:
TIME
-----------------------
2016-12-31 23:59:33.000
注意:建议使用新的leap秒时，您需要使软件包保持最新.
更新:
SELECT COUNT(*) "EVENTS",
TRUNC(
TIMESTAMP '1970-01-01 00:00:00.000'
+ NUMTODSINTERVAL( MSSTAMP / 1000, 'SECOND' ),
'MM'
) "FINISHED_MONTH"
FROM DB_TABLE
WHERE MSSTAMP < 1483228800000
AND STATUS = 'FINISHED'
GROUP BY
TRUNC(
TIMESTAMP '1970-01-01 00:00:00.000'
+ NUMTODSINTERVAL( MSSTAMP / 1000, 'SECOND' ),
'MM'
);
这篇关于如何在Oracle中将以毫秒为单位的时间戳转换为日期的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！