Python Matplotlib从绘图中使用光标获取数据

问题描述

，大家好，我使用的是python> matplotlib，我想通过使用光标从图中获取数据.

, Hi guys, I'm using python>matplotlib and I want to get the data from the plot by using the cursor.

import numpy as np
import matplotlib.pyplot as plt
t = np.arange(0., 2., 0.1)
plt.plot(t,t,'g^')
ax = plt.gca()
line = ax.lines[0]
xd = line.get_xdata()
yd = line.get_ydata()
valx = np.where(xd==xd[0])
plt.show()

在图中，从0,0到1.9,1.9会有19个点；所以...

In the plot there will be 19 dots from 0,0 to 1.9,1.9; so...

当我先单击0,0然后单击0.3,0.3时，我想获取值:

When I click on 0,0 first and then on 0.3,0.3, I want to get the values:

(0,0);
(0.1,0.1);
(0.2,0.2);
(0.3,0.3)

有没有办法做到这一点?

Is there a way to do this?

但是还有一个问题，就是光标必须在该点上，有没有办法将光标定位在图形而不是其他点上?

But also there's a problem that the cursor has to be over the point, is there a way to position the cursor on the graphic and not other point???

推荐答案

有一个在matplotlib页面上的选择器示例.您可以对其进行调整，以在单击第n个点时显示前n个点对.

There is a Picker example on the matplotlib page. You can adapt it to show the first n point pairs when the nth point is clicked.

import numpy as np
import matplotlib.pyplot as plt
t = np.arange(0., 2., 0.1)
line, = plt.plot(t,t,'g^', picker=6)

def click(event):
    artist = event.artist
    ind = event.ind[0]
    xd = artist.get_xdata()[:ind]
    yd = artist.get_ydata()[:ind]
    print( zip(xd, yd) )

cid = plt.gcf().canvas.mpl_connect("pick_event", click)

plt.show()

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