问题描述
我需要加入我在Powershell中创建的两个表.问题在于它们共享的5列中,每个表中的两列都不同.如何连接这两个表,然后对其进行排序.我猜我将要执行以下两个操作:
I need to join two tables that I have created in Powershell. The problem is that out of the 5 columns they share, two columns are different in each table. How can I join these two tables, and then be able to sort them. I am guessing I would have two do the following:
示例:表格1列:a,b,c,d,e
Example:table1Columns: a, b, c, d, e
表2列a,x,c,d,z
table2Columns a, x, c, d, z
我是否必须向每个空的表中添加一个新列,但要代表另一个表中缺少的列,以便在执行table1 + table2时,它们不会删除任何数据?
Do I have to add a new column to each table that is empty but to represent the column it is missing from the other table, so that when I do table1 + table2, they do not drop any data?
没有sql连接内容的代码示例.
Example of the code without sql connection stuff.
$Command.CommandText = "SELECT job_number, job_desc, permit_number, pieces, rate, postage_total FROM monticello_charges WHERE (insert_date >= '$from') AND (insert_date < '$to') ORDER BY job_number"
$Command2.CommandText = "SELECT job_number, description, permit_number, pieces, rate, total FROM mailshop_charges WHERE (mailing_date >= '$from') AND (mailing_date < '$to')ORDER BY permit_number, job_number"
$Reader = $Command.ExecuteReader()
$Reader2 = $Command2.ExecuteReader()
###################################
#Do not add entries that have a [permit_number] of (360) and [rate] less than (0)
###################################
$results = @()
while ($Reader.Read())
{
$row = [ordered]@{}
for ($i = 0; $i -lt $Reader.FieldCount; $i++)
{
if($reader.GetValue(2) -eq 360 -and $reader.GetValue(4) -lt 0)
{
#pass over it
}
else
{
$row[$reader.GetName($i)] = $reader.GetValue($i)
}
}
$results += new-object psobject -property $row
}
###################################
# Build the second table and replace 280 permits to (M)
###################################
$results2 = @()
while ($Reader2.Read())
{
$row = [ordered]@{}
for ($i = 0; $i -lt $Reader2.FieldCount; $i++)
{
if($i -eq 2 -and $reader2.GetValue($i) -eq 280)
{
$row[$reader2.GetName($i)] = "M"
#$counter++
}
else
{
$row[$reader2.GetName($i)] = $reader2.GetValue($i)
}
}
$results2 += new-object psobject -property $row
}
$connection.Close();
$connection2.Close();
###################################
#Combine the tables and sort,then inject to CSV output file.
##################################
$finalResult = $results + $results2;
#$finalResult = $finalResult | sort-object @{Expression = {$_.permit_number}; Ascending = $true},{$_.job_number}
$finalResult | sort-object @{Expression = {$_.permit_number}; Ascending = $true},{$_.job_number} | export-csv c:\Users\cpharr\Desktop\out.csv
Write-Host "Report has been exported to current directoy. Filename:[out.csv]"
提前谢谢!
推荐答案
好吧,假设您没有链接条目并且所有记录都是单独的,则可以执行以下操作:
Ok, assuming you don't have linked entries and all the records are separate you could do this:
$T2Keys = $Results2|gm|?{$_.MemberType -match "Property"}|Select -ExpandProperty Name
$T1Keys = $Results|gm|?{$_.MemberType -match "Property"}|Select -ExpandProperty Name
$KeysToAdd = $T2Keys|?{$T1Keys -notcontains $_}
$Results3 = @()
$Results3 += $Results
$KeysToAdd|%{$Results3|Add-Member $_ ""}
$Results3+=$Results2
这将第一个表的属性查询到一个变量.它对第二张表也一样.它找到第二个表中的属性,而不是第一个表中的属性,并将它们保存到变量中.然后,它生成一个空数组,向其中添加第一个表,添加缺少的字段,然后向其添加第二个表.
That queries the properties of the first table to a variable. It does the same to the second table. It finds the properties that are in the second table that aren't in the first one and saves them to a variable. Then it makes an empty array, adds the first table to it, adds the missing fields, then adds the second table to it.
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