问题描述
我需要用两行GridLayoutManager创建一个recyclerView,并且第一个元素要比其余元素大.结果应如下所示:
I need to create a recyclerView with a GridLayoutManager on two lines, and the first element to be bigger than the rest. The result should look like this:
我设法做到了,但是以一种非常规的方式.在我的recyclerView适配器中,我为第一个元素使用了一个不同的viewHolder,即一个更大的元素.那将是一个很好的解决方案,但是第二个元素将低于第一个元素.因此,我给了一个技巧,使recyclerView的固定高度与第一个元素相同,这样第一个元素和第二个元素将重叠,而我只是简单地使第二个元素的可见性消失了.
I managed to achieve this, but in an unconventional way. In my recyclerView adapter I use a different viewHolder for the first element, a bigger one. That would have been a great solution, but the second element would have gone below the first element. So I made a trick of giving recyclerView a fixed height same as the first element, that way the first element and the second would overlap and I would simply make the visibility of the second to gone.
@Override
public RecyclerView.ViewHolder onCreateViewHolder(ViewGroup parent, int viewType) {
switch (viewType) {
case 0:
final View view = inflater.inflate(R.layout.big_item, parent, false);
return new BigViewHolder(view);
case 2:
final View view2 = inflater.inflate(R.layout.normal_item, parent, false);
return new NormalViewHolder(view2);
default:
return null;
}
}
@Override
public void onBindViewHolder(RecyclerView.ViewHolder holder, int position) {
if (position == 1) {
holder.itemView.setVisibility(View.GONE);
}}
@Override
public int getItemViewType(int position) {
if (position == 0) {
return 0;
} else return 2;
}
但是我并不特别喜欢这种方法.有人对此有更好的主意吗?
But I don't particularly like this approach. Does anyone have a better idea on this?
推荐答案
经过一番挖掘和咨询,我得出了很好的结果.我将其发布在下面:
After some digging and counseling, I came to a pretty nice result. I will post it below:
首先,适配器应该看起来像我在问题中提到的那样,而没有隐藏第二个元素:
First, the adapter should look like I mentioned in the question, without the hiding of the second element:
public class MyAdapter extends RecyclerView.Adapter<RecyclerView.ViewHolder> {
public static final int TYPE_FIRST_ITEM = 0;
public static final int TYPE_ITEM = 1;
@Override
public RecyclerView.ViewHolder onCreateViewHolder(ViewGroup parent, int viewType) {
switch (viewType) {
case TYPE_FIRST_ITEM:
final View view = inflater.inflate(R.layout.big_item, parent, false);
return new BigViewHolder(view);
case TYPE_ITEM:
final View view2 = inflater.inflate(R.layout.normal_item, parent, false);
return new NormalViewHolder(view2);
default:
return null;
}
}
@Override
public void onBindViewHolder(RecyclerView.ViewHolder holder, int position) {
switch (holder.getItemViewType()) {
case TYPE_FIRST_ITEM:
BigViewHolder bigViewHolder = (BigViewHolder) holder;
// Do what you need for the first item
break;
case TYPE_ITEM:
NormalViewHolder normalViewHolder = (NormalViewHolder) holder;
// Do what you for the other items
break;
}
}
@Override
public int getItemViewType(int position) {
if (position == 0) {
return TYPE_FIRST_ITEM;
} else return TYPE_ITEM;
}
final class NormalViewHolder extends RecyclerView.ViewHolder {
public NormalViewHolder(View itemView) {
super(itemView);
}
// find your views here
}
final class BigViewHolder extends RecyclerView.ViewHolder {
public BigViewHolder(View itemView) {
super(itemView);
}
// find your views here
}
}
第二,布局管理器应实现一个侦听器,以指定在特定位置应有多少跨度(行):
Second, the layout manager should implement a listener to specify how many spans (rows) should be at a specific position:
RecyclerView mRecyclerView = view.findViewById(R.id.my_recycler_view);
MyAdapter mAdapter = new MyAdapter();
GridLayoutManager mLayoutManager = new GridLayoutManager(getActivity(), 2, LinearLayoutManager.HORIZONTAL, false);
mLayoutManager.setSpanSizeLookup(new GridLayoutManager.SpanSizeLookup() {
@Override
public int getSpanSize(int position) {
switch(mAdapter.getItemViewType(position)){
case MyAdapter.TYPE_FIRST_ITEM:
return 2;
case MyAdapter.TYPE_ITEM:
return 1;
default:
return -1;
}
}
});
mRecyclerView.setAdapter(mAdapter);
mRecyclerView.setLayoutManager(mLayoutManager);
希望它也会对其他人有帮助.谢谢迈克M. 的支持.
Hope it will help someone else too. Thank you Mike M. for your support.
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