问题描述
我有一个Flutter应用程序,正在其中使用StreamProvider监听Firebase的身份验证更改以显示正确的屏幕.我想做的是将FirebaseUser映射到自定义的User对象,该对象将从Firestore检索,以使其可以从小部件树中的任何位置进行访问.
I have a Flutter app in which I'm listening to auth changes from Firebase to display the correct screen, using a StreamProvider. What I would like to do is to map the FirebaseUser to a custom User object, which would be retrieved from Firestore, to have it accessible from anywhere in the widget tree.
有什么办法可以做到这一点?
Is there any way to achieve this?
我现在正在做什么:
class AuthService {
final FirebaseAuth _auth = FirebaseAuth.instance;
Stream<FirebaseUser> get user {
return _auth.onAuthStateChanged;
}
}
class MyApp extends StatelessWidget {
@override
Widget build(BuildContext context) {
return StreamProvider<FirebaseUser>.value(
value: AuthService().user,
child: MaterialApp(...)
推荐答案
首先,从自定义模型开始,确定您想要的东西,在这种情况下,我将简单地使用 uid
First, start with the custom model and decide what you would like to have, in this case I will simply have the uid
class User {
final String uid;
User({ this.uid });
}
AuthService
// Create user object based on FirebaseUser
User _customModelForFirebaseUser(FirebaseUser user) {
return user != null ? User(uid: user.uid) : null;
}
// auth changed user stream
Stream<User> get user {
return _auth.onAuthStateChanged
.map(_customModelForFirebaseUser)
}
我的应用
class MyApp extends StatelessWidget {
@override
Widget build(BuildContext context) {
return StreamProvider<User>.value(
value: AuthService().user,
child: MaterialApp(
home: Wrapper(),
),
);
}
}
然后您可以从任何地方访问它,就像这样:
Then you can access it from anywhere, like so:
@override
Widget build(BuildContext context) {
final user = Provider.of<User>(context);
}
这篇关于将FirebaseUser映射到自定义User对象的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!