本文介绍了解析JSON数据并将其放入gridview的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我正在开发一个应用程序,其中必须解析JSON
数据并将其放入自定义gridview
中.这就是它的外观.
I'm developing an application in which I have to parse JSON
data and have to put them in custom gridview
. Here is what it should look like.
到目前为止,我已经在asynctask中解析了JSON数据并获取了这些值.这是我的代码:
So far I have parsed my JSON data in asynctask and getting those values. Here is my code:
private class getRedeemData extends AsyncTask<String, Void, String> {
@Override
protected void onPreExecute() {
super.onPreExecute();
pdia = new ProgressDialog(AllPerksActivity.this);
pdia.setMessage("Loading products. Please wait...");
pdia.show();
}
@Override
protected String doInBackground(String... args) {
HttpParams params = new BasicHttpParams();
params.setParameter(CoreProtocolPNames.PROTOCOL_VERSION,
HttpVersion.HTTP_1_1);
HttpClient httpClient = new DefaultHttpClient(params);
HttpPost post = new HttpPost(
"MY API HERE..!!");
post.setHeader("Content-Type", "application/x-www-form-urlencoded");
try {
post.setEntity(new StringEntity("client_id=" + client_id + "&"
+ "client_secret=" + clientSecretKey, HTTP.UTF_8));
HttpResponse response = httpClient.execute(post);
int i = response.getStatusLine().getStatusCode();
System.out.println("HTTP Post status AllPerk Redeemption API: "
+ i);
BufferedReader in = new BufferedReader(new InputStreamReader(
response.getEntity().getContent()));
// SB to make a string out of the inputstream
StringBuffer sb = new StringBuffer("");
String line = "";
String NL = System.getProperty("line.separator");
while ((line = in.readLine()) != null) {
sb.append(line + NL);
}
in.close();
// the json string is stored here
String result = sb.toString();
System.out.println("Result Body: " + result);
return result;
} catch (Exception e) {
// TODO: handle exception
}
return null;
}
@Override
protected void onPostExecute(String result) {
JSONObject jObject;
try {
jObject = new JSONObject(result);
JSONArray jSearchData = jObject.getJSONArray("rewards");
for (int i = 0; i < jSearchData.length(); i++) {
JSONObject objJson = jSearchData.getJSONObject(i);
String rewardID = objJson.getString("rewardID");
String rewardType = objJson.getString("rewardType");
String rewardTitle = objJson.getString("rewardTitle");
System.out.println("Reward ID: " + rewardID);
System.out.println("Reward Type: " + rewardType);
System.out.println("Reward Tittle: " + rewardTitle);
}
} catch (Exception e) {
// TODO: handle exception
}
pdia.dismiss();
}
}
这是我的Gridview XML:
Here is my XML for Gridview:
<?xml version="1.0" encoding="utf-8"?>
<GridView xmlns:android="http://schemas.android.com/apk/res/android"
android:id="@+id/grid"
android:layout_width="fill_parent"
android:layout_height="fill_parent"
android:horizontalSpacing="10dp"
android:numColumns="2"
android:scrollbarStyle="outsideOverlay"
android:scrollbars="vertical"
android:verticalScrollbarPosition="right"
android:verticalSpacing="10dp" >
</GridView>
有人可以告诉我如何使用适配器解决此问题.
Can some one tell my how to use adapter for this problem.
任何帮助将不胜感激.
推荐答案
您将JSON数据保存在某个数组中,然后
You save the JSON data in some array and then
gridView.setAdapter(new ImageAdapter(this, MOBILE_OS));
对于带有定制适配器的Gridview,请参阅此链接
Refer to this link for Gridview with custom adapter
http://www.mkyong.com/android/android-gridview-example/
这篇关于解析JSON数据并将其放入gridview的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!