问题描述
我有一条从 A 点到 B 点的线；我有 (x,y) 两点.我还有一个以 B 为中心的矩形以及矩形的宽度和高度.
I have a line that goes from points A to B; I have (x,y) of both points. I also have a rectangle that's centered at B and the width and height of the rectangle.
我需要找到与矩形相交的直线中的点.有没有一个公式可以给我那个点的 (x,y)?
I need to find the point in the line that intersects the rectangle. Is there a formula that gives me the (x,y) of that point?
推荐答案
假设矩形是轴对齐的，这让事情变得非常简单:
Assuming the rectangle is axis-aligned, this makes things pretty simple:
直线的斜率是 s = (Ay - By)/(Ax - Bx).
The slope of the line is s = (Ay - By)/(Ax - Bx).
- 如果 -h/2
- 如果 Ax > Bx 则为右边缘
- 如果 Ax < 则为左边缘Bx.
- 如果 Ay > By 的顶边
- 如果 Ay
- 则为底边作者.
一旦你知道它相交的边，你就会知道一个坐标:x = Bx ± w/2 或 y = By ± h/2，具体取决于你碰到的边.另一个坐标由 y = By + s * w/2 或 x = Bx + (h/2)/s 给出.
Once you know the edge it intersects you know one coordinate: x = Bx ± w/2 or y = By ± h/2 depending on which edge you hit. The other coordinate is given by y = By + s * w/2 or x = Bx + (h/2)/s.
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