Libgdx - 从Rectangle.overlap获取交集矩形（矩形）

问题描述

有没有办法知道像矩形在C＃中的 ？

Is there any way to know the intersection Rectangle area between two Rectangles in libgdx like the Rectangle in c# http://msdn.microsoft.com/en-us/library/microsoft.xna.framework.rectangle.intersect.aspx ?

我需要获得两个矩形，但在libgdx重叠法之间的交集矩形区域只返回布尔值两个矩形是否相交与否。
我已阅读部门间类，但它提供了没事做。

I need to get the intersection rectangle area between that two rectangles but the overlap method in libgdx only return boolean value whether two rectangles are intersect or not.I have read Intersector class but it provides nothing to do that.

感谢您

推荐答案

事实上，LibGDX没有内置此功能，所以我会做这样的事情：

Indeed, LibGDX does not have this functionality built in, so I would do something like this:

/** Determines whether the supplied rectangles intersect and, if they do,
 *  sets the supplied {@code intersection} rectangle to the area of overlap.
 *
 * @return whether the rectangles intersect
 */
static public boolean intersect(Rectangle rectangle1, Rectangle rectangle2, Rectangle intersection) {
    if (rectangle1.overlaps(rectangle2)) {
        intersection.x = Math.max(rectangle1.x, rectangle2.x);
        intersection.width = Math.min(rectangle1.x + rectangle1.width, rectangle2.x + rectangle2.width) - intersection.x;
        intersection.y = Math.max(rectangle1.y, rectangle2.y);
        intersection.height = Math.min(rectangle1.y + rectangle1.height, rectangle2.y + rectangle2.height) - intersection.y;
        return true;
    }
    return false;
}

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