问题描述
可能的重复: 在 java 中打印正则表达式匹配
我在 java 中使用 Matcher 类将字符串与特定的正则表达式匹配，我使用 Pattern 类将其转换为 Pattern.我知道我的正则表达式有效，因为当我执行 Matcher.find() 时，我得到了我应该得到的真实值.但是我想打印出产生这些真实值的字符串(意思是打印出与我的正则表达式匹配的字符串)并且我在匹配器类中没有看到实现这一点的方法.请让我知道是否有人以前遇到过这样的问题.我很抱歉，因为这个问题相当初级，但我对正则表达式还很陌生，因此我仍在探索正则表达式世界.
I am using Matcher class in java to match a string with a particular regular expression which I converted into a Pattern using the Pattern class. I know my regex works because when I do Matcher.find(), I am getting true values where I am supposed to. But I want to print out the stings that are producing those true values (meaning print out the strings that match my regex) and I don't see a method in the matcher class to achieve that. Please do let me know if anyone has encountered such a problem before. I apologize as this question is fairly rudimentary but I am fairly new to regex and hence am still finding my way around the regex world.
推荐答案
假设 m 是你的匹配器:
Assuming mis your matcher:
m.group() 将返回匹配的字符串.
m.group() will return the matched string.
添加了有关匹配组的信息
Added info regarding matched groups
此外，如果您的正则表达式在括号内有部分，m.group(n) 将返回与括号内的第 n 个组匹配的字符串；
Also, if your regex has portions inside parenthesis, m.group(n) will return the string that matches the nth group inside parenthesis;
Pattern p = Pattern.compile("mary (.*) bob");
Matcher m = p.matcher("since that day mary loves bob");
m.group() 返回玛丽爱鲍勃".m.group(1) 返回loves".
m.group() returns "mary loves bob".m.group(1) return "loves".
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