添加重复值

问题描述

我有

int [] array1 = {1,2,3,4,2,4,5}

int [] array2 = {7,8 ，9,10,4.4,2,3}



i想要输出如下



int [] array1 = {1,2,3,4,5}

int [] array2 = {7,12.4,12,10,4.4,3}



添加重复项 - 比如2重复，2在array2中有8,4.4值

与array1中重复4相同，它在array2中的值为10和2

现在我希望2的显示值是12.4,4的值是12.



我尝试了什么：



尝试下面的解决方案

i have
int[] array1 = {1,2,3,4,2,4,5}
int[] array2 = {7,8,9,10,4.4,2,3}

i want output like below

int[] array1 = {1,2,3,4,5}
int[] array2 = {7,12.4,12,10,4.4,3}

addition of duplicates - like 2 is repeated and 2 has 8,4.4 values in array2
same as 4 is repeated in array1 and it has values 10 and 2 in array2
now i want show value for 2 is 12.4 and value for 4 is 12.

What I have tried:

tried below solution

class Program
	{
		public static void Main(string[] args)
		{
			int [] sArray = {10,20,30,40,40,50,60};
			var sList = new ArrayList();

			for (int i = 0; i < sArray.Length; i++) {
			    if (sList.Contains(sArray[i]) == false) {
			        sList.Add(sArray[i]);
			    }
			}

			var sNew = sList.ToArray();

			for (int i = 0; i < sNew.Length; i++) {
			    Console.Write(sNew[i]);
			}
			Console.ReadLine();
		}
	}

推荐答案

Each time you find a duplicate in array1 at position x and y,
    you add array2[y] to array2[x]
    remove array2[y] and array1[y]

您只需要将其翻译成代码。

You just have to translate this to code.

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