本文实例为大家分享了python实现人民币转大写人民币的具体代码，供大家参考，具体内容如下
直接上代码：
# -*- coding: utf-8 -*-
def changenum( change_number ):
format_num = ["零","壹","贰","叁","肆","伍","陆","柒","捌","玖"]
format_name = ["分", "角", "元",
"拾","百","千","万",
"拾","百","千","亿",
"拾","百","千","万",
"拾","百","千","兆"]
if type( change_number ) == str:
if '.' in change_number:
try: change_number = float( change_number )
except: raise ValueError, '%s can\'t change'%change_number
else:
try: change_number = int( change_number )
except: raise ValueError, '%s can\'t change'%change_number
if type( change_number ) == float:
real_numbers = []
for i in range( len( format_name ) - 3, -3, -1 ):
if change_number >= 10 ** i or i < 1:
real_numbers.append( int( round( change_number/( 10**i ), 2)%10 ) )
elif isinstance( change_number, (int, long) ):
real_numbers = [ int( i ) for i in str( change_number ) + '00' ]
else:
raise ValueError, '%s can\'t change'%change_number
zflag = 0
start = len(real_numbers) - 3
change_words = []
for i in range(start, -3, -1):
if 0 <> real_numbers[start-i] or len(change_words) == 0:
if zflag:
change_words.append(format_num[0])
zflag = 0
change_words.append( format_num[ real_numbers[ start - i ] ] )
change_words.append(format_name [i+2])
elif 0 == i or (0 == i%4 and zflag < 3):
change_words.append(format_name [i+2])
zflag = 0
else:
zflag += 1
if change_words[-1] not in (format_name[0], format_name[1]):
change_words.append("整")
return ''.join(change_words)
#测试
# print changenum(865324.98)
#查看输出的结果是否正确
以上就是本文的全部内容，希望对大家的学习有所帮助，也希望大家多多支持脚本之家。