将十六进制编码的字符串转换为字符串

问题描述

我想在Swift 3中转换以下十六进制编码的String

I want to convert following hex-encoded String in Swift 3:

dcb04a9e103a5cd8b53763051cef09bc66abe029fdebae5e1d417e2ffc2a07a4

与其等价的String:

Ü°J:\ص7cï  ¼f«à)ýë®^A~/ü*¤

以下网站做得很好:

http://codebeautify.org/hex-string-converter

http://string-functions.com/hex-string.aspx

但是我无法在Swift 3中做同样的事情.以下代码也无法完成这项工作:

But I am unable to do the same in Swift 3. Following code doesn't do the job too:

func convertHexStringToNormalString(hexString:String)->String!{
  if let data = hexString.data(using: .utf8){
      return String.init(data:data, encoding: .utf8)
  }else{ return nil}
}

推荐答案

您要使用十六进制编码的数据作为AES密钥，但是数据不是有效的UTF-8序列.您可以解释它以ISO Latin编码形式作为字符串，但AES(key: String, ...)初始化程序将字符串转换回其UTF-8表示形式，也就是说，您将获得与开始时不同的关键数据.

You want to use the hex encoded data as an AES key, but thedata is not a valid UTF-8 sequence. You could interpretit as a string in ISO Latin encoding, but the AES(key: String, ...)initializer converts the string back to its UTF-8 representation,i.e. you'll get different key data from what you started with.

因此，您根本不应该将其转换为字符串.使用

Therefore you should not convert it to a string at all. Use the

extension Data {
    init?(fromHexEncodedString string: String)
}

来自在Swift中进行十六进制/二进制字符串转换的方法将十六进制编码的字符串转换为Data，然后将其传递作为AES(key: Array<UInt8>, ...)初始值设定项的数组:

method from hex/binary string conversion in Swiftto convert the hex encoded string to Data and then pass thatas an array to the AES(key: Array<UInt8>, ...) initializer:

let hexkey = "dcb04a9e103a5cd8b53763051cef09bc66abe029fdebae5e1d417e2ffc2a07a4"
let key = Array(Data(fromHexEncodedString: hexkey)!)

let encrypted = try AES(key: key, ....)

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