本文介绍了如何更改波纹状可绘制对象的纯色?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
<?xml version="1.0" encoding="utf-8"?>
<ripple xmlns:android="http://schemas.android.com/apk/res/android"
android:color="?android:attr/colorControlHighlight">
<item>
<selector>
<item android:state_selected="true">
<layer-list>
<item android:left="-5dp"
android:top="-5dp"
android:right="-5dp">
<shape android:shape="rectangle">
<stroke android:width="3dp"
android:color="@android:color/white"/>
<solid android:color="@android:color/transparent"/>
</shape>
</item>
</layer-list>
</item>
<item android:state_selected="false">
<shape android:shape="rectangle">
<solid android:color="@android:color/transparent"/>
</shape>
</item>
</selector>
</item>
</ripple>
这是我的涟漪可绘制对象,我想更改 state_selected ,纯色颜色.
here is my ripple drawable and i want to change the state_selected, solid color.
我尝试过的代码:
RippleDrawable rippleDrawable = (RippleDrawable) textView.getBackground(); // assumes bg is a RippleDrawable
int[][] states = new int[][]{new int[]{android.R.attr.state_selected}};
int[] colors = new int[]{R.color.white};
ColorStateList colorStateList = new ColorStateList(states, colors);
rippleDrawable.setColor(colorStateList);
不幸的是,它不起作用.我想念什么,这可能吗?
unfortuantely it doesn't work.. what am I missing and is this possible?
推荐答案
您应在项目中添加一个ID,以通过Java/kotlin访问它们.
检查此背景XML文件
You should add an id to items to access them via java/kotlin.
check this background XML file
<?xml version="1.0" encoding="utf-8"?>
<ripple xmlns:android="http://schemas.android.com/apk/res/android"
android:color="#e0e0e0">
<item android:id="@+id/fab_shape">
<shape xmlns:android="http://schemas.android.com/apk/res/android"
android:shape="rectangle">
<corners android:radius="25dp" />
<solid android:color="@color/colorAccent" />
</shape>
</item>
</ripple>
要更改其纯色,请在constraintLayout背景上应用此可绘制的XML
to change the solid color of this, on constraintLayout background, this drawable XML is applied
val background = constraintLayout.background as RippleDrawable
val bgShape = background.findDrawableByLayerId(R.id.fab_shape) as GradientDrawable
bgShape.color = color
供参考阅读
这篇关于如何更改波纹状可绘制对象的纯色?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!