的结果的生存期是多少

的结果的生存期是多少

本文介绍了std :: string :: c_str()的结果的生存期是多少?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

在我的一个程序中,我必须与一些与 const char * 一起使用的旧代码对接.

In one of my programs, I have to interface with some legacy code that works with const char*.

让我们说一个结构如下:

Lets say I have a structure which looks like:

struct Foo
{
  const char* server;
  const char* name;
};

我的上层应用程序仅处理 std :: string ,所以我想到了使用 std :: string :: c_str()取回const char * 指针.

My higher-level application only deals with std::string, so I thought of using std::string::c_str() to get back const char* pointers.

但是 c_str()的生​​存期是多少?

But what is the lifetime of c_str() ?

我可以做这样的事情而不会遇到不确定的行为吗?

Can I do something like this without facing undefined behavior ?

{
  std::string server = "my_server";
  std::string name = "my_name";

  Foo foo;
  foo.server = server.c_str();
  foo.name = name.c_str();

  // We use foo
  use_foo(foo);

  // Foo is about to be destroyed, before name and server
}

还是我应该立即将 c_str()的结果复制到另一个地方?

Or am I supposed to immediately copy the result of c_str() to another place ?

谢谢.

推荐答案

如果 std :: string 被破坏或非字符串的-const成员函数被调用.因此,如果您需要保留它,通常会希望对其进行复制.

The c_str() result becomes invalid if the std::string is destroyed or if a non-const member function of the string is called. So, usually you will want to make a copy of it if you need to keep it around.

在您的示例中,看来似乎安全地使用了 c_str()的结果,因为在该范围内不会修改字符串.(但是,我们不知道 use_foo()〜Foo()可能对这些值做了什么;如果它们将字符串复制到其他位置,则应该执行真正的 copy ,而不仅仅是复制 char 指针.)

In the case of your example, it appears that the results of c_str() are used safely, because the strings are not modified while in that scope. (However, we don't know what use_foo() or ~Foo() might be doing with those values; if they copy the strings elsewhere, then they should do a true copy, and not just copy the char pointers.)

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09-02 11:23