本文介绍了Jackson用时间戳字段反序列化JSON的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我有这样的字符串:

{
   "debug":"false",
   "switchTime":"2017-04-12 17:04:42.896026"
}

我正在尝试通过这种方法获取对象:

I'm trying to get object in such approach:

new ObjectMapper().readValue(string, MyObject.class);

和MyObject类:

And MyObject class:

class MyObject {
    private Boolean debug;
    private Timestamp switchTime;
    //...getters, setters, constructors
}

我有这样的例外:

com.fasterxml.jackson.databind.exc.InvalidFormatException:
Can not deserialize value of type java.sql.Timestamp from String
"2017-04-12 17:04:42.896026": not a valid representation (error:
Failed to parse Date value '2017-04-12 17:04:42.896026':
Can not parse date "2017-04-12 17:04:42.896026Z": while it seems
to fit format 'yyyy-MM-dd'T'HH:mm:ss.SSS'Z'',
parsing fails (leniency? null))  at [Source:
{"debug":"false", "switchTime":"2017-04-12 17:04:42.896026"};

我不明白为什么...如果我在调试模式下使用Timestamp.valueOf()和"2017-04-12 17:04:42.896026"-我成功了

I don't understand why...If i use in debug mode Timestamp.valueOf() with "2017-04-12 17:04:42.896026" - i have success

推荐答案

我认为您需要使用@JsonFormat注释设置预期的日期/时间格式,如下所示.

I think you need to set the expected date/time format using @JsonFormat annotation as shown below.

class MyObject {
  private Boolean debug;
  @JsonFormat(pattern="yyyy-MM-dd HH:mm:ss.SSS")
  private Timestamp switchTime;
  //...getters, setters, constructors
}

您还可以将时区设置为@JsonFormat(pattern="yyyy-MM-dd HH:mm:ss.SSS",timezone="PST")

You can also set timezone as @JsonFormat(pattern="yyyy-MM-dd HH:mm:ss.SSS",timezone="PST")

这篇关于Jackson用时间戳字段反序列化JSON的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!

09-02 11:19