问题描述
考虑Microsoft提供的示例: https://docs.microsoft.com/zh-cn/dotnet/framework/wcf/how-to-create-a-wcf-client
Consider the example Microsoft has on: https://docs.microsoft.com/en-us/dotnet/framework/wcf/how-to-create-a-wcf-client
如何使用一个简单的HttpClient对象使用服务器?
How can one consume the server using a simple HttpClient object?
在某些情况下,无法向您的项目添加Web引用.然后,使用HttpClient对象可能是唯一的方法……或者将Server DLL引用添加到客户端也是一种选择.
There are instances where adding a Web Reference to your project is not possible. Then, using an HttpClient object might be the only way ... or adding a Server DLL reference to the Client side could also be an option.
这应该是一个简单的示例,说明如何调用以下所述的简单double = Add(double,double)函数:
This should be a simple example of how to call the simple double = Add(double, double) function described under:
namespace GettingStartedLib
{
// NOTE: You can use the "Rename" command on the "Refactor" menu to change the interface name "IService1" in both code and config file together.
[ServiceContract]
public interface ICalculator
{
[OperationContract]
double Add(double n1, double n2);
}
}
服务器端如下所示:
namespace GettingStartedLib
{
public class CalculatorService : ICalculator
{
public double Add(double n1, double n2)
{
double result = n1 + n2;
Console.WriteLine("Received Add({0},{1})", n1, n2);
// Code added to write output to the console window.
Console.WriteLine("Return: {0}", result);
return result;
}
}
}
推荐答案
您可以使用http客户端发送一个引用Fiddle捕获的请求内容的http请求.
You could use http client to send a http request refer to the request content captured by Fiddle.
POST http://10.157.18.36:12000/Service1.svc HTTP/1.1 Content-Type: text/xml; charset=utf-8 SOAPAction: "http://tempuri.org/IService1/Add" Host: 10.157.18.36:12000 Content-Length: 161 Expect: 100-continue Accept-Encoding: gzip, deflate Connection: Keep-Alive
<s:Envelope xmlns:s="http://schemas.xmlsoap.org/soap/envelope/"><s:Body><Add xmlns="http://tempuri.org/"><n1>34.23</n1><n2>80.54</n2></Add></s:Body></s:Envelope>
基于Web服务规范的WCF服务.
https://en.wikipedia.org/wiki/Web_service
他们使用肥皂消息通过http/https协议相互通信.在这种情况下,我们可以使用httpclient模仿请求.
除此之外,wcf还可以通过http-mode发布服务,就像Asp.net Web API一样,风格样式也很宁静.
https://docs.microsoft. com/en-us/dotnet/framework/wcf/wcf-and-aspnet-web-api
我做了一个演示,希望它对您有用.
IService1
WCF Service based on the web service specification.
https://en.wikipedia.org/wiki/Web_service
They use soap message to communicate with each other via http/https protocol.In that cases, we could use the httpclient to imitate the request.
Beside, wcf also could publish the service via http-mode, just like Asp.net web api, restful style structure.
https://docs.microsoft.com/en-us/dotnet/framework/wcf/wcf-and-aspnet-web-api
I have made a demo, wish it is useful to you.
IService1
[ServiceContract]
public interface IService1
{
[OperationContract]
[WebGet(ResponseFormat =WebMessageFormat.Json,RequestFormat =WebMessageFormat.Json)]
Double Add(double n1, double n2);
}
Service1.svc.cs
public class Service1 : IService1
{
public double Add(double n1, double n2)
{
return n1 + n2;
}
}
配置.
<system.serviceModel>
<services>
<service name="WcfService1.Service1">
<endpoint address="" binding="webHttpBinding" contract="WcfService1.IService1" behaviorConfiguration="rest"></endpoint>
<endpoint address="mex" binding="mexHttpBinding" contract="IMetadataExchange"></endpoint>
</service>
</services>
<behaviors>
<endpointBehaviors>
<behavior name="rest">
<webHttp/>
</behavior>
</endpointBehaviors>
<serviceBehaviors>
<behavior>
<serviceMetadata httpGetEnabled="true" httpsGetEnabled="true" httpGetUrl="mex"/>
<serviceDebug includeExceptionDetailInFaults="true"/>
</behavior>
</serviceBehaviors>
</behaviors>
<protocolMapping>
<add binding="basicHttpsBinding" scheme="https" />
</protocolMapping>
<serviceHostingEnvironment aspNetCompatibilityEnabled="true" multipleSiteBindingsEnabled="true" />
</system.serviceModel>
客户.
static void Main(string[] args)
{
HttpClient client = new HttpClient();
var result=client.GetStringAsync("http://localhost:9001/Service1.svc/add?n1=1.2&n2=3.2");
Console.WriteLine(result.Result);
}
结果.
随时让我知道是否有什么可以帮助您的.
Result.
Feel free to let me know if there is anything I can help with.
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