Django REST序列化程序：创建对象而不保存

问题描述

我已经开始玩Django REST框架了。我想要做的是使用一些JSON POST请求，从中创建一个Django Model对象，并使用该对象而不保存该对象。我的Django模型叫做SearchRequest。我有的是：

  @api_view（['POST']）
 def post_calculation（request）：
如果request.method =='POST'：
 #JSON到序列化对象
 serializer = SearchRequestSerializer（data = request.data）
 if（serializer.is_valid（）== False） ：
 return响应（serializer.errors，status = status.HTTP_400_BAD_REQUEST）
 mySearchRequestObject = serializer.save（）
  

这样做会创建一个SearchRequest对象，但是立即将其保存到数据库中。我将需要它而不保存。

解决方案

将此方法添加到您的 SearchRequestSerializer class

  def create（self，validated_data）：
 return SearchRequest（** validated_data）
  

并在函数 post_calculation 中调用它，而不是保存，如下所示：

  mySearchRequestObject = serializer.create（）
  




I have started to play with the Django REST framework. What I am trying to do is to POST a request with some JSON, create a Django Model object out of it, and use the object without saving it. My Django model is called SearchRequest. What I have is:

@api_view(['POST'])
def post_calculation(request):
    if request.method == 'POST':
        #JSON to serializer object
        serializer = SearchRequestSerializer(data=request.data)
        if (serializer.is_valid() == False):
            return Response(serializer.errors, status=status.HTTP_400_BAD_REQUEST)
        mySearchRequestObject = serializer.save()

This does create a SearchRequest object, however saves it into the database right away. I would need it without saving.

解决方案

Add this method to your SearchRequestSerializer class

def create(self, validated_data):
    return SearchRequest(**validated_data)

And call it in function post_calculation instead of save, like so:

mySearchRequestObject = serializer.create()

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