UIImageView在tableView单元格中更改图像

UIImageView在tableView单元格中更改图像

本文介绍了iOS swift UIImageView在tableView单元格中更改图像的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我在 tableView 自定义单元格中有一个奇怪的问题。对于类似Image动作,我在Custom cell 中编写这些代码,名为 FeedViewCell

I have a strange problem in tableView Custom cell. for like Image action I write these code in Custom cell called FeedViewCell:

self.like.isUserInteractionEnabled = true
let CommenttapGestureRecognizer = UITapGestureRecognizer(target:self, action:#selector(likehandleTap))
self.like.addGestureRecognizer(CommenttapGestureRecognizer)

func likehandleTap(_ sender: UITapGestureRecognizer) {

    if self.like.image == UIImage(named: "like-btn-inactive") {

        self.like.image = UIImage(named: "like-btn-active")

    } else {
        self.like.image = UIImage(named: "like-btn-inactive")
    }
}

和TableViewController :

and TableViewController:

func tableView(_ tableView: UITableView, cellForRowAtIndexPath indexPath: IndexPath) -> UITableViewCell {

    let cell = tableView.dequeueReusableCell(withIdentifier: "FeedCell", for: indexPath) as! FeedViewCell

    return cell
}

但正如您所见触摸时视频索引0中的类似按钮并改变图像,索引3中的类似按钮也改变图像。你能告诉我我的错误吗?

but as you see in this video when I touch the like button in index 0 and change the image, the like button in index 3 change image also. can you guys tell me my mistake please?

谢谢

推荐答案

尝试使用100%的代码

  var selectindex : Int?
  var selectedindex : NSMutableArray = NSMutableArray()
  @IBOutlet var tableview: UITableView!

func tableView(tableView: UITableView, cellForRowAtIndexPath indexPath: NSIndexPath) -> UITableViewCell {
        let cell = tableView.dequeueReusableCellWithIdentifier("LikeCell", forIndexPath: indexPath)

        let like: UIButton = (cell.viewWithTag(2) as! UIButton)
        let comment: UIButton = (cell.viewWithTag(3) as! UIButton)
        if selectedindex.containsObject(indexPath.row) {
                like.setBackgroundImage(UIImage.init(named: "like.png"), forState: .Normal)
        }else{
                like.setBackgroundImage(UIImage.init(named: "like (1).png"), forState: .Normal)
        }
       comment.setBackgroundImage(UIImage(named: "chat.png"), forState: UIControlState.Normal)
        like.addTarget(self, action: #selector(self.CloseMethod(_:event:)), forControlEvents: .TouchDown)
        comment.addTarget(self, action: #selector(self.CloseMethod1(_:event:)), forControlEvents: .TouchDown)

        return cell

    }



 @IBAction func CloseMethod(sender: UIButton, event: AnyObject) {

        let touches = event.allTouches()!
        let touch = touches.first!
        let currentTouchPosition = touch.locationInView(self.tableview)
        let indexPath = self.tableview.indexPathForRowAtPoint(currentTouchPosition)!
        selectindex = indexPath.row
        if selectedindex.containsObject(selectindex!) {
            selectedindex.removeObject(selectindex!)
        }else{
              selectedindex.addObject(selectindex!)
        }
        self.tableview.reloadData()
    }

这篇关于iOS swift UIImageView在tableView单元格中更改图像的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!

09-02 09:19