在UITableViewCell中显示UIMenuController，分组样式

问题描述

是否有一种简单的方法可以在点击单元格时实现复制菜单，而不是对UITableViewCell进行子类化?

Is there a simple way to implement the copy menu when a cell is tapped, instead of subclassing the UITableViewCell?

谢谢

RL

推荐答案

是的！
从- (void)tableView:(UITableView *)tableView didSelectRowAtIndexPath:(NSIndexPath *)indexPath(UITableView的委托方法)中调用[[UIMenuController sharedMenuController] setMenuVisible:YES animated:ani](其中ani是BOOL确定控制器是否应设置动画)

Yes!
Call [[UIMenuController sharedMenuController] setMenuVisible:YES animated:ani] (where ani is a BOOL determining whether the controller should be animated) from within - (void)tableView:(UITableView *)tableView didSelectRowAtIndexPath:(NSIndexPath *)indexPath ( UITableView's delegate method)

默认情况下，UIMenuController上的复制"命令不会复制detailTextLabel.text文本.但是，有一种解决方法.将以下代码添加到您的课程中.

The 'copy' command on the UIMenuController will not by default copy the detailTextLabel.text text. However, there is a workaround. Add the following code into your class.

-(void)copy:(id)sender {
    [[UIPasteboard generalPasteboard] setString:detailTextLabel.text];
}


- (BOOL)canPerformAction:(SEL)action withSender:(id)sender {
    if(action == @selector(copy:)) {
        return YES;
    }
    else {
        return [super canPerformAction:action withSender:sender];
    }
}

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